Figure #5 shows 5 squares which I would assume means (5, 5)
In the table you have the point (3, 7)
From this you can find the slope: (7 - 5)/(3 - 5) = -1
Completions of table:
x y
0 10
1 9
2 8
3 7
4 6
5 5
6 4
Rule/Equation:
y = -x + 10
Graph: Plot the ordered pairs from the table
Just answers since long and many simplifiction
it's like doing those multiplication memory things that had like 100 questions but now with algebra fractions
5. fourth or

6. third or

7.the answe ris x+3 since it can be factored out of the 5x+15 tingie (second )
8. fourth or

9. fourth or

times
10. third or

11. second or
12. third or 11(x+7)=60
9514 1404 393
Answer:
(b) One figure is a rotation image of the other
Step-by-step explanation:
The axis of symmetry is horizontal for the left figure, and vertical for the right figure. The right figure has been rotated 90° CW from the left figure.
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27