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Phoenix [80]
3 years ago
8

A toy rocket is launched from a platform 42 feet above the ground at a speed of 91 feet per second. The height of the rocket in

feet is given by the polynomial −16t^2 + 91t + 42, where t is the time in seconds. How high will the rocket be after 3 seconds? HELP ASAP!!
A. 122 feetB. 218 feetC. 93 feetD. 2570 feet
Mathematics
1 answer:
True [87]3 years ago
3 0
Lets get started!

height = -16t² + 91t + 42 
After 3 sec means, t = 3, so we substitute t with 3

H = -16(3)² + 91(3) + 42
    = -144 + 273 + 42
    = 171 feet
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General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (-7,5)\ (-4,1)\ into\ equation\\\\ 
\left \{ {{5=-7a+b}\ \ \ \ \atop {1=-4a+b\ |*-1}} \right.\\\\ \left \{ {{5=-7a+b}\ \ \ \ \atop {-1=4a-b}} \right.\\\\
+----\\\\Addition\ method\\\\
4=-3a\ \ |:(-3)\\\\
a=-\frac{4}{3}\\\\
b=5+7a=5+7*(-\frac{4}{3})=5-\frac{28}{3}=-4\frac{1}{3}\\\
Answer\ y=-\frac{4}{3}x-4\frac{1}{3}\\\\
Checking\ solution:\\
y-5=-\frac{4}{3}(x+7)
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