Question

A toy rocket is launched from a platform 42 feet above the ground at a speed of 91 feet per second. The height of the rocket in feet is given by the polynomial −16t^2 + 91t + 42, where t is the time in seconds. How high will the rocket be after 3 seconds? HELP ASAP!!
A. 122 feetB. 218 feetC. 93 feetD. 2570 feet

Answer 1

Lets get started!

height = -16t² + 91t + 42 
After 3 sec means, t = 3, so we substitute t with 3

H = -16(3)² + 91(3) + 42
    = -144 + 273 + 42
    = 171 feet