If you’re looking for expressions for those,
1. 20x + 30
2. 45x
Answer: SU = 4(1) + 1 = 5
Step-by-step explanation:
Since T is on segment SU we know the whole is eqaul to the sum of it’s parts.
ST + TU = SU substitute
3x - 1 + 3x = 4x + 1 simplify
6x - 1 = 4x + 1 solve for x
2x = 2
x = 1
ST = 3(1) -1 = 2
TU = 3(1) = 3
SU = 4(1) + 1 = 5
6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
Answer: 6r^3 - 15r
Step-by-step explanation:
(3r) (2r^2 - 5)
Distribute.
6r^3 - 15r
Hope this helped.
Step-by-step explanation:
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