They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:
y=150-600t x=200-800t
By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:
d^2=y^2+x^2, using y and x from above
d^2=(150-600t)^2+(200-800t)^2
d^2=22500-180000t+360000t^2+40000-320000t+640000t^2
d^2=1000000t^2-500000t+62500
d=√(1000000t^2-500000t+6250)
So the rate of change is the derivative of d
dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)
dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)
So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...
...
To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...
1000000t^2-500000t+62500=0
6250(16t^2-8t+1)=0
6250(16^2-4t-4t+1)=0
6250(4t(4t-1)-1(4t-1))=0
6250(4t-1)(4t-1)=0
6250(4t-1)^2=0
4t-1=0
4t=1
t=1/4 hr
Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)
To solve this equation, lets move all of the variables to one side of the equation and the constants to the other.
0.12x - 1.5 = 0.24x - 0.06
Subtract 0.12x from both sides of the equation
-1.5 = 0.12x - 0.06
Add 0.06 to both sides of the equation
-1.44 = 0.12x
Divide both sides by 0.12 to isolate x
x = -12
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
X< -10/3
Interval Notation:
(-∞, - 10/3)
Hope this is right :)
Answer:
just typed the whole in mathaway.com
Step-by-step explanation:
it's a better app for quadratic equation and you can use it on a school computer
Answer:
D
Step-by-step explanation:
So you can protect your eyes.
