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Sophie [7]
3 years ago
14

48 cookies; 25% decrease how do I do it?????

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0
Step One: Find 25% of 48.
Step Two: Subtract that number from 48.

48 * 0.25 = 12
48 - 12 = 36

36 cookies
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SOLVE THE SIMULATENOUS EQUATIONS Y=X-2 AND Y= 3X+5
natta225 [31]

Answer: y = x-2

y = 3x + 5

x-2 = 3x+5

x+3x = 5+2

4x = 7

x = 7/4

y = x-2

y = 7/4 - 2

y = 7-8/4

y = -1/4

3 0
2 years ago
PLEASE HELP ASAP T^T
chubhunter [2.5K]

9514 1404 393

Answer:

  no feasible solutions

Step-by-step explanation:

There are so many inequalities that determining the area covered by all 5 of them is problematic. Hence, we have reversed all of them in the attached graph, so any feasible solution region would remain white. Alas, there is no such region.

This system of inequalities has <em>no feasible solution</em>.

3 0
2 years ago
There are a total of 18 frocks. If the ratio of purple frocks to white frocks is 2 to 4, how many of them are white?
Oksana_A [137]
I think it will be 2:4. 2X9=18 so u × 4×9=36 so its 18 to 36
7 0
3 years ago
The frequency of the musical note C4 is about 261.63 Hz. What is the frequency of the note a perfect fifth below C4?
kolbaska11 [484]

Answer:

The frequency of the note a perfect fifth below C4 is;

B- 174.42 Hz

Step-by-step explanation:

Here we note that to get the "perfect fifth" of a musical note  we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have

1.5 × Frequency of note Y = Frequency of C4

1.5 × Y = 261.63

Therefore, Y = 261.63/1.5 = 174.42 Hz.

6 0
2 years ago
Which of the following statements is not true? a) The standard deviation of the sampling distribution of sample mean = σ/√n b) T
I am Lyosha [343]

Answer:

e) The mean of the sampling distribution of sample mean is always the same as that of X, the distribution from which the sample is taken.

Step-by-step explanation:

The central limit theorem states that

"Given a population with a finite mean μ and a finite non-zero variance σ2, the sampling distribution of the mean approaches a normal distribution with a mean of μ and a variance of σ2/N as N, the sample size, increases."

This means that as the sample size increases, the sample mean of the sampling distribution of means approaches the population mean.  This does not state that the sample mean will always be the same as the population mean.

6 0
3 years ago
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