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Contact [7]
3 years ago
6

Solving systems of equations has been used consistently throughout this course in order to shed light on all kinds of different

situations, i.e. finding the intersection point of a system of linear equations, finding eigenvectors, etc. List at least two different types of problems that require solving a system of linear equations, explain how solving a system of linear equations is used, and what information can be learned from the solution.
Mathematics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

Types of problems that require solving a system of linear equations are:

Calculation of mileage rate

Calculations of ages of children born to a family

Calculation of income over a range of period.

Step-by-step explanation:

Solving a system of linear equations have many real life applications. Many real life problems can be used to set up a system of linear equations.

The following are the steps:

Understand the problem

Break the problem down into parts and represent each part with unknown variables such as: X1, X2, X3,...

Combine the unknown variables mathematically, from the statements of the problem(That is, 2X1 + X2 - 6X3, X1 + 2X2 + 4X3,....)

The results of the solved linear equation system (after solving) will give the solution to the problem. The solutions to the real life problems can be learned by the nature, analysis, and relationship of the solutions of the system of the formed linear equation

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The Length of one side of a parallelogram is 3 more than twice the length of the adjacent side. The perimeter of the parallelogr
katovenus [111]

Answer: 4 cm and 11 cm.


Step-by-step explanation:

1. You can calculate the perimeter of a parallelogram as following:

P=a+b+c+d

Where a+b+c+d are the lenghts of the sides.

By definition the parallelogram has two pairs of parallel sides, therefore:

a=c and b=d

Then, you can calculate the perimeter as following:

 P=2(a+b)

2. Let's call the adjacent side x, then the other side is 2x+3.

3. Substitute values  and solve for x:

30=2(x+2x+3)\\30=2(3x+3)\\30=6x+6\\24=6x\\x=4

4. Then the lenghts of the sides are:

x=4cm\\2x+3=2(4cm)+3=11cm


5 0
4 years ago
74.362 to the nearest tenth
max2010maxim [7]

Answer:

73.4

Step-by-step explanation:

When they ask for the nearest tenth you check the hundreth, it its 5 or ore than you increase the tenth

8 0
3 years ago
An exam consists of two parts, Section X and Section Y. There can be a maximum of 95 questions. There must be at least 20 more q
GuDViN [60]

Answer:

X + Y <= 95.

Y >= 20+ X.

Step-by-step explanation:

It is given that section X and section Y can have hardly 95 questions.

Hence either both have them has total 95 questions or less than 95 questions.

If we take X as the number of questions section X has and Y as the number of questions section Y has then X + Y <= 95.

Also it is given that Y has at least more 20 more questions than Y has. Hence Y can have 20 more question than X has or more than 20 more question than X.

That is Y >= 20+ X.

As shown in the graph the line passing through (95, 0) and (0, 95) the arrows are towards the origin because the origin satisfies the equation.

In the other line the origin that is (0, 0) does not satisfy the equation. Hence the arrows will not be towards the origin.

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False, it is on the horizontal.
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you are buying a shirt that is 14$ but you realize its 30% off. How much is the shirt. Explain how to find the cost.
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The shirt is now 4$ and 20 cents off, which makes it's cost 9$ and 80 cents.

Step-by-step explanation:

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3 years ago
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