The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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988
A year later will depreciate $294
The following year $253
On the third year $217
The fourth year. $187
And the 5th year. $161
Answer:
IDK
nvm its writ 5 in beths colum
sorry for my spelling
Step-by-step explanation:
i got it right on apex
Answer:
X= 15
Step-by-step explanation:
multiply 5 on x/5 and 9
divide 3 and 45
x=15
Answer: The answer would be c
Step-by-step explanation:
Step 1: Solve for b
5a+b=7
b=-5a+7
your slope would be -5a
Step 2: Make it perpendicular
The Perpendicular is gonna be the opposite
So it would be b= 1/5+7
The slopes has to be different and you don't have to worry about the "+7"
Reply if you have any questions
