Answer:
1.the slope is 1/2 and the y int is -4
2.the slope is -3 and the y int is 6
Answer: (2,4)
Step-by-step explanation:
Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
Answer:
6. r=2
8.x=3
Step-by-step explanation:
6. 4r-3=5
4r-3=5 add 3 to both sides
4r=8 divide 4 by both sides
r=2
8. 5x-6=9
5x-6=9 add 6 to both sides
5x=15 divide 5 by both sides
x=3
<span>The reference angle is closest to the x-axis.
I will assume the above is 7pi/6. That would be a reference angle of pi/6, and the sin in the 3rd quadrant is negative, so the sin theta = - 0.5</span>