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krek1111 [17]
2 years ago
9

What is -11n=77 answer fast!

Mathematics
1 answer:
Rom4ik [11]2 years ago
5 0

Answer:

-7 bro

Step-by-step explanation:

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Jonathan is deciding between two truck rental companies. Company A
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Answer:

Jonathan is deciding between two truck rental companies. Company A

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3 years ago
Solve for x: <br><br> -4x +8 = 42<br><br> x =
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A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min
sesenic [268]
A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})
\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}
A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4

We're given that A(0)=30. Multiply both sides by the integrating factor e^{t/100}, then

e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4
\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4
e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C
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Given that A(0)=30, we have

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so the amount of salt in the tank at time t is

A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}
3 0
3 years ago
Como faz esta conta 6-4x=-20-10x
yulyashka [42]
6-4x=20-10x, 2+20=-10x+4x, x=26/-6
4 0
3 years ago
Read 2 more answers
Asymptote of f(x)=2^x+3
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