This can be solve by 3 variable equation
let x be the money of luke
y money of rachel
z money of daniel
first equation
x = y + 21
second equation
x = z + 48
third equation
x + y + z = 168
solving simultaneously
x =79
y = 58
z = 31
15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
<h3>What is a permutation?</h3>
A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.
Now,
= 13!/(13-5)!
= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444
Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
To learn more about the permutation visit:
brainly.com/question/1216161.
#SPJ1
Answer:
21
Step-by-step explanation:
Because h(3) times h(7) is equal to 21.
Hope it helps!
Your answer would be 3 and 1/8