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3 years ago

Plz Help ASAP!

Mathematics

1 answer:

Rina8888 [55]3 years ago

5 0

Part A:

From the graph, it seems that the lines intersect at (3,-1)... This seems to be the solution...

Part B:
g(x) is a negative line, and the slope is 2 (from rise/run). Y int. = 5. So, the equation is -2x+5. Plug in some numbers for this; say 1 and 2. The coordinates would be (1,3) and (2,1).

Part C:
The 2 graphs seem to intersect at (0,5), so this is the solution...

ALL of this is based on only looking at the graph, which is no better than drawing lines on the sand.. For example, the y intercept for g(x) could be 4.9 or 5.1, and I don't know the equation for f(x)... Based on the info I have, gave my best answers..

Hope this helps..

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BARSIC [14]

Answer:

C) $y=-0.5x+8$

Step-by-step explanation:

Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.

All the given options for the line of best fit are linear equations.

Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.

Linear equation: $y=mx+b$

(where $m$ is the slope and $b$ is the y-intercept)

From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 8. So this suggests that options C or D are the solution.

We can also see that the slope (gradient) of the line of best fit is approximately -0.5 (as the rate of change (y/x) is -1 unit of y for every +2 units of x).

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lana66690 [7]

Answer:

The first term in the sequence is odd-valued and so there are m choices for it.2020 Gauss Contest Solutions Page 19

The second term in the sequence is even-valued and so there are m − 1 choices for it.

Thus, there are a total of m × (m − 1) FT sequences that begin with an odd-valued term

followed by an even-valued term.

Finally, we consider the FT sequences that begin with an even-valued term followed by an

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Again, there are exactly twice as many odd-valued terms as there are even-valued terms in the

first 2019 terms (since the pattern repeats even, odd, odd).

However in this case, the 2020th term is even and so there are fewer than twice as many odd valued terms as there are even-valued terms.

Thus, there are m2 + m × (m − 1) FT sequences that satisfy the required conditions.

Since there are 2415 such FT sequences, we may solve m2 + m × (m − 1) = 2415 by trial and

error.

Evaluating m2 + m × (m − 1) when m = 30, we get 302 + 30 × 29 = 1770, and so m is greater

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When m = 33, we get 332 + 33 × 32 = 2145.

When m = 34, we get 342 + 34 × 33 = 2278.

When m = 35, we get 352 + 35 × 34 = 2415, as required.

Answer: (D)

Step-by-step explanation:

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