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3 years ago

Plz Help ASAP!

Mathematics

1 answer:

Rina8888 [55]3 years ago

5 0

Part A:

From the graph, it seems that the lines intersect at (3,-1)... This seems to be the solution...

Part B:
g(x) is a negative line, and the slope is 2 (from rise/run). Y int. = 5. So, the equation is -2x+5. Plug in some numbers for this; say 1 and 2. The coordinates would be (1,3) and (2,1).

Part C:
The 2 graphs seem to intersect at (0,5), so this is the solution...

ALL of this is based on only looking at the graph, which is no better than drawing lines on the sand.. For example, the y intercept for g(x) could be 4.9 or 5.1, and I don't know the equation for f(x)... Based on the info I have, gave my best answers..

Hope this helps..

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Answer:

$A = 43.0^o$

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Step-by-step explanation:

I will solve this question with the attached triangle

From the attachment, we have:

$\angle C =82^o$

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$AC = 24$

Required

Solve the triangle

First, we calculate $\angle B$ using sine law:

$\frac{AC}{\sin(B)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{24}{\sin(B)} = \frac{29}{\sin(82^o)}$

$\frac{24}{\sin(B)} = \frac{29}{0.9903}$

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Divide both sides by 29

$\sin(B) = 0.8196$

Take arcsin of both sides

$B = \sin^{-1}(0.8196)$

$B = 55.0^o$

Next, calculate $\angle A$ using:

$A + B + C = 180^o$ --- angles in a triangle

$A + 55^o + 82^o = 180^o$

Collect like terms

$A = 180^o-55.0^o - 82^o$

$A = 43.0^o$

Next, calculate BC using sine laws

$\frac{BC}{\sin(A)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{BC}{\sin(43.0)} = \frac{29}{\sin(82)}$

$\frac{BC}{0.6820} = \frac{29}{0.9903}$

Make BC the subject

$BC = \frac{29*0.6820}{0.9903}$

$BC = 20.0$

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