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olasank [31]
3 years ago
13

Can someone please help me with my homework ASAP? It's due tonight.

Chemistry
2 answers:
sladkih [1.3K]3 years ago
3 0

Answer:

27.7 grams of Li

0.140 moles of Co

0.158 moles of K

59.9 grams of As

8.00x10⁻⁹ moles of U

142.8 moles of H

0.0199 moles of O

0.666 moles of Pb

Explanation:

Mass / Molar mass = Mol

Mol . Molar mass = Mass

3.99 m . 6.94 g/m = 27.7 grams of Li

8.28 g / 58.93 g/m = 0.140 moles of Co

6.17 g / 39.1 g/m = 0.158 moles of K

0.8 mol . 74.92 g/m = 59.9 grams of As

6.02x10²³ (NA) particles are contained in 1 mol

6.02x10²³ are contained in 1 mol U____ 1 mol  H ____ 1 mol O ___ 1 mol Pb

4.82x10¹⁵ atoms U  ____ 4.82x10¹⁵/ 6.02x10²³ = 8.00x10⁻⁹ moles of U

8.60x10²⁵atoms H  ____ 8.60x10²⁵ / 6.02x10²³  = 142.8 moles of H

1.20x10²² atoms O  ____ 1.20x10²² / 6.02x10²³ = 0.0199 moles of O

4.01x10²³ atoms Pb ____ 4.01x10²³ / 6.02x10²³ = 0.666 moles of Pb

Stolb23 [73]3 years ago
3 0

Answer:

1) 27.69 grams Li

2) 0.138 moles Co

3) 0.0736 moles Kr

4) 59.94 grams As

5) 8*10^-9 moles U  = 1.9*10^-6 grams U

6) 142.81 moles H = 144.24 grams H

7) 0.0199 moles O = 0.3184 grams

8) 0.666 moles Pb = 138 grams

Explanation:

Step 1: Data given

Moles = mass / molar mass

mass = moles * molar mass

3.99 mol Li to g Li

⇒ Molar mass of Li = 6.94 g/mol

mass of Li = 3.99 grams * 6.94 g/mol = 27.69 grams

8.28 g Co to mol Co

⇒ Molar mass of Co = 58.93 g/mol

Moles of Co = 8.28 grams / 59.93 g/mol = 0.138 moles

⇒ Molar mass of Kr = 83.80 g/mol

Moles of Kr = 6.17 grams / 83.80 g/mol = 0.0736 moles

0.8000 mol As to g As

⇒ Molar mass of As = 74.92 g/mol

Mass of As = 0.8000 mol * 74.92 g/mol =  59.94 grams

4.82*10^15 atoms U

⇒ 1 mol = 6.022*10^23 atoms

4.82*10^15  = 1/6.022*10^23 * 4.82*10^15 = 8*10^-9 moles U

8*10^-9 moles U *238.03 = 1.9*10^-6 grams

8.60*10^25 atoms H

⇒ 1 mol = 6.022*10^23 atoms

8.60*10^25  = 1/6.022*10^23 * 8.60*10^25 = 142.81 moles U

142.81 moles H *1.01 = 144.24 grams

1.20*10^22 atoms O

⇒ 1 mol = 6.022*10^23 atoms

1.20*0^22  = 1/6.022*10^23 * 1.20*10^22 =0.0199 moles U

0.0199 moles O * 16g/mol = 0.3184 grams

4.01*10^23 atoms Pb

⇒ 1 mol = 6.022*10^23 atoms

4.01*10^23  = 1/6.022*10^23 * 4.01*10^23 =0.666 moles U

0.666 moles Pb * 207.2 g/mol = 138 grams

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Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

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Where, T_1 and T_2 are initial and final temperatures, P_1 and P_2 are initial and final pressures.

T_1 = 20.3 + 273.15 = 293.45 K

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Let's plug in the values in the equation and solve it for final pressure.

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3. The temperature of a fixed mass of gas in a rigid container is decreased from 127.00 degrees
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Answer:

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