It's 77C.......................
C because it is two seperate mixtures I think
Answer:
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The new volume of air trapper in the cylinder is determined as 116.56 mL.
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New volume of air in the cylinder</h3>
The volume of air trapper in the cylinder is determined from Boyle's law;
P₁V₁ = P₂V₂
where;
- P₁ is initial pressure = 1.08 atm
- V₁ is initial volume = 145.7 mL
- P₂ is new pressure = 1.25 x 1.08 atm = 1.35 atm
- V₂ is new volume = ?
V₂ = (P₁V₁)/P₂
V₂ = (1.08 x 145.7)/1.35
V₂ = 116.56 mL
Thus, the new volume of air trapper in the cylinder is determined as 116.56 mL.
Learn more about volume here: brainly.com/question/1972490
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The grams of Mg(OH)2 produced is calculated as below
calculate the moles of HCl produced =molarity xvolume/1000
= 0.3 x 435/1000= 0.1305 moles
write the equation for reaction
Mg(OH)2 +2HCl = MgCl2 + 2H2O
by use of mole ratio between HCl :MgCl2 which is 2 :1 the moles of HCl = 0.1305 x1/2 =0.0653 moles of MgCl2
mass of MgCl2 = moles x molar mass
= 0.0653mol x95 g/mol = 6.204 grams of MgCl2
