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omeli [17]
3 years ago
15

Rank the following by their miscibility in

Chemistry
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

<h2>2. H2O < CH3OH < CH3CH2OH < C9H20</h2>

Explanation:

Decane is a hydrocarbon so it is a non-polar molecule. Non-polar molecules are soluble in non-polar molecules and polar molecules are soluble in polar molecules. Water is a polar molecule so it is least soluble in decane molecule and C_{9}H_{20} is a non-polar molecule so it is most soluble in decane molecule. Methanol and ethanol are the derivatives of hydrocarbon so they have more solubility than water but less solubility than nonane molecules.

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Liters of a 2.40 M
kotykmax [81]

Answer:

1.42 L

Explanation:

Step 1:

The following data were obtained from the question :

Molarity of KBr = 2.40 M

Mole of KBr = 3.40 moles

Volume of solution =?

Step 2:

Determination of the volume of the solution.

Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 3.4/2.4

Volume = 1.42 L

Therefore, the volume of the solution is 1.42 L

6 0
3 years ago
What is the energy of an electromagnetic wave with a frequency of 8•10^12 Hz?
aniked [119]

Hello!

Find the Energy of the Photon by Planck's Equation, given:

E (photon energy) =? (in Joule)

h (Planck's constant) = 6.626*10^{-34}\:J * s

f (radiation frequency) = 8*10^{12}\:Hz

Therefore, we have:

E = h*f

E = 6.626*10^{-34}*8*10^{12}

E = 53.008*10^{-34+12}

E = 53.008*10^{-22}

\boxed{\boxed{E = 5.3008*10^{-21}\:Joule}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

8 0
3 years ago
Density = _____<br> (A)weight/length<br> (B)mass/weight<br> (C)mass/volume<br> (D)volume/weight
8_murik_8 [283]
Density= Mass/Volume I am positive I just had an assignment on this
7 0
3 years ago
Read 2 more answers
H-E-L-P!!...!! ʕ ꈍᴥꈍʔ​
N76 [4]

Answer:

the correct answer is (2)

Explanation:

4 0
2 years ago
Read 2 more answers
What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?
Law Incorporation [45]
The answer is 0.975 L

Volume = mol/Molarity

We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:

Molar mass of CaCl2 is sum of atomic masses of Ca and Cl:
Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol

So, if 110.9 g are in 1 mol, 85.3 g will be in x mol:
110.9 g : 1 mole = 85.3 g : x
x = 85.3 g * 1 mole / 110.9
x = 0.769 moles

Now, calculate the volume:
V = 0.769/0.788
V = 0.975 L
5 0
3 years ago
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