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omeli [17]
3 years ago
15

Rank the following by their miscibility in

Chemistry
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

<h2>2. H2O < CH3OH < CH3CH2OH < C9H20</h2>

Explanation:

Decane is a hydrocarbon so it is a non-polar molecule. Non-polar molecules are soluble in non-polar molecules and polar molecules are soluble in polar molecules. Water is a polar molecule so it is least soluble in decane molecule and C_{9}H_{20} is a non-polar molecule so it is most soluble in decane molecule. Methanol and ethanol are the derivatives of hydrocarbon so they have more solubility than water but less solubility than nonane molecules.

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garik1379 [7]
I think unbalanced? not sure sorry
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3 years ago
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Which models of the atom include a structure that is mostly made of empty space?RutherfordThomsonBohrQuantum mechanical
Luba_88 [7]
<h2>Answer:</h2>

Rutherford's models

<h2>Explanations:</h2><h2>What is the electron cloud model?</h2>

There are known as the region where electrons are found especially in the nucleus.

According to the five basic atomic models which have contributed to the structure of the atom itself, the Rutherford's models of the atom include a structure that is mostly made of empty space compared to thomson that proposed the plum pudding model of the atom

4 0
1 year ago
Pls help me i dont know this
r-ruslan [8.4K]

Answer:

1. 12.6 moles

2. 8.95 moles

3.  2A + 5B → 3C

4. 48 moles

Explanation:

1. 2Fe + 3Cl₂ → 2FeCl₃

We assume the chlorine in excess. Ratio is 2:2

2 moles of Fe, can produce 2 moles of chloride

12.6 moles of Fe will produce 12.6 moles of chloride.

2. 2Fe + 3Cl₂ → 2FeCl₃

For the same reaction, first of all we need to convert the mass to moles:

500 g . 1mol / 55.85 g = 8.95 mol

As ratio is 2:2, the moles we have are the same, that the produced

4. The reaction for the combustion is:

2C₂H₆ (g) + 7O₂ (g) → 4CO₂ (g) + 6H₂O (l)

We assume the oxygen in excess.

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Therefore 16 moles of ethane may produce (16 .6) / 2 = 48 moles

3 0
3 years ago
A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution
madam [21]

<u>Answer:</u> The initial pH of the HCl solution is 3

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL

Putting values in above equation, we get:

1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M

1 mole of HCl produces 1 mole of H^+ ions and 1 mole of Cl^- ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.001M

Putting values in above equation, we get:

pH=-\log (0.001)\\\\pH=3

Hence, the initial pH of the HCl solution is 3

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3 years ago
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Answer:

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Explanation:

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