Write the complete ionic equation for the reaction that takes place when aqueous solutions of strontium hydroxide and lithium ph
1 answer:
Answer : The net ionic equation will be,
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The given balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
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Answer:
The correct answer is:48.5% X-59, 51.5% X-61
Explanation:
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of X-59 isotope be 'x'. So, fractional abundance of X-61 isotope will be '1 - x'
For X-59 isotope:
Mass of X-59 isotope =59 g/mol
Fractional abundance of X-59 isotope = x
For X-61 isotope:
Mass of X-61 isotope = 61 g/mol
Fractional abundance of X-61 isotope = 1 - x
Average atomic mass of chlorine = 35.4527 amu
Putting values in equation 1, we get:
Percentage abundance of X-59 isotope =
Percentage abundance of X-61 isotope =
Hence, the percentage abundance of both the isotopes X-59and X-61 are 51.5% and 48.5% respectively.