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3 years ago

Angle A is circumscribed about circle O. What is the measure of angle O?

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

3 0

Step-by-step explanation:

is Al Gore a circumscribed about six times the measure of angle is 180 degrees

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Given the algebraic expression the quantity 64 times x to the two-thirds power end quantity to the negative one-third power comm

11111nata11111 [884]

The given algebraic expression is equal to 1 divided by the quantity 4 times x to the two-ninths power end quantity. The correct option is B.

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The given algebraic expression can be simplified using the exponential properties. Therefore, the simplification of the algebraic expression can be done as shown below.

$(64x^{\frac23})^{-\frac13}$

$= (4^3)^{-\frac13} \times x^{(\frac23 \times -\frac13)}\\\\= 4^{(3 \times -\frac13)} \times x^{(\frac23 \times -\frac13)}\\\\= 4^{-1} \times x^{-\frac29}\\\\=\dfrac{1}{4x^{\frac29}}$

Hence, the correct option is B.

Learn more about Expression here:

brainly.com/question/13947055

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3 0

2 years ago

The midpoint of ab is M (-1,-1).If the coordinates of A are (3,-6),what are the coordinates of B

daser333 [38]

Answer:-3,4

Step-by-step explanation:

8 0

3 years ago

Write the point slope equation of the line through (7,-2) with slope of 1/2.

ahrayia [7]

Answer:

y = 0.5x - 5.5

Step-by-step explanation:

slope = 0.5, so this is the x coefficient.

y intercept = -2 - (7 x 0.5) = -5.5

4 0

3 years ago

Let X be a positive continuous random variable with density fXpxq. Let Y " lnpXq. (a) Find the density fY pyq of Y in terms of t

salantis [7]

Answer:

X density = fXpxq and

Y" =InpXq

Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"

fX = In

And PXq =pxq

Thus replacing x with y,

PXq = pyq

(a) Hence the density of Y is FYpyq

(b) at p0, fYpyq =fYp0q= 0

At 5s, FYpyq =5

7 0

3 years ago

Read 2 more answers

How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6

REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have

it goes like this:

for a polynomial with real coefients, consider $f(x)=-3x^6-2x^4+5x+6$ .

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root

to get the negative roots, we evaluate f(-x) and see how many times the root changes

$f(-x)=-3x^6-2x^4-5x+6$

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root

a total of 2 real roots

a function of degree $n$ can have at most, $n$ roots

our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots

you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0

3 years ago