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4 years ago

15

What is the length of segment AB? 20 POINTS PLS HELP pls I WILL MARK YOU AS BRAINEST

2 answers:

solniwko [45]4 years ago

7 0

This segment creates a right triangle with the x and y axis. The two legs are 8 units and 6 units. Using the Pythagorean theorem, we know that 8^2+6^2=x^2, when x is the length of AB. 8^2+6^2=100.
Therefore, 100=x^2
We can then take the square root of both sides to find that:
x=10.
Hope this is helpful!

marishachu [46]4 years ago

6 0

it should be a answer choice there

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Read 2 more answers

Explain why the function of f(x)=4x^2+8x is neither even or odd

myrzilka [38]

Answer:

By putting x = -x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

Step-by-step explanation:

We need to explain why the function of $f(x)=4x^2+8x$ is neither even or odd

First we will understand, when the function is even and odd

Even function:

<em>A function is even if f(-x) = f(x) </em>

Odd function:

<em>A function is odd if f(-x) = -f(x) </em>

So, if we get the above result by putting x = -x, then we can say that the function is even or odd.

If we don't get any of the above results then the function is neither even nor odd.

So, for the given function: $f(x)=4x^2+8x$

Put x = -x

$f(x)=4x^2+8x\\Put x=-x\\f(-x)=4(-x)^2+8(-x)\\f(-x)=4x^2-8x$

So, by putting x=-x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

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