2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6
Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
Answer:
mad is 0
Step-by-step explanation:
what type of question is this? no offense
Answer:What is -12 subtracted from the sum of -19 and 11?
Step-by-step explanation: 4 IS YOU ANSWER
Answer:
Step-by-step explanation:
Answer:
589 is da answer
Step-by-step explanation:
25+6(94)=?
