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gizmo_the_mogwai [7]
3 years ago
8

The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballga

me (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52. From the given scenario, we can conclude that events A and B are . NextReset
Mathematics
2 answers:
Zolol [24]3 years ago
8 0

The quick answer all you edmentum/plato users are looking for is

dependent events since P(A and B) is not equal to P(A) * P(B)

cricket20 [7]3 years ago
4 0

<u>Events</u> A and B are called <u>independent</u>, when

Pr(A\cap B)=Pr(A)\cdot Pr(B),

otherwise events A and B are <u>dependent</u>.

The events A, B and A∩B are:

  • A - Jane will go to a ballgame on Monday;
  • B - Kate will go to a ballgame on Monday;
  • A∩B - Kate and Jane both go to the ballgame on Monday.

Pr(A)=0.73,\ Pr(B)=0.61,\ Pr(A\cap B)=0.52.\\ \\ Pr(A)\cdot Pr(B)=0.73\cdot 0.61=0.4453\neq 0.52=Pr(A\cap B).

Answer: events A and B are dependent


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