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4 years ago

Anyone know? Help is appreciated! Will mark brainliest if correct!

Mathematics

2 answers:

serious [3.7K]4 years ago

4 0

D. 6 is correct answer

Andre45 [30]4 years ago

4 0

Answer:

6 is the correct answer

Step-by-step explanation:

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What is the probability that the spinner lands on an odd number both spins?

Mnenie [13.5K]

Answer:66.667

Step-by-step explanation:

4 0

3 years ago

1) If 6 jalapenos are used, how many anaheims will be used? (just numbers...no labels)

Assoli18 [71]

By counting the table entries, we can see that there are 10 different options for a 3-topping pizza.

The different toppings ought on a pizza are:

As a general rule of thumb, I recommend selecting three to five toppings for each pizza you create.

Because mozzarella is a basic component of every pizza I prepare, it does not qualify as a topping.

Other cheeses that can be used as toppings are goat cheese, feta, and smoked gouda.

The most common supreme toppings are pepperoni, link, immature bell pepper, ebony olives, and red onions.

Sautéed mushrooms or even hot peppers are frequently incorporated.

Even though the sauce and cheese should almost always go on the bottom, the toppings themselves usually require the greatest attention.

Regardless of how many layers your pizza has, the top layer will receive the most heat.

Thus, by counting the table entries, we can see that there are 10 different options for a 3-topping pizza.

To learn more about 3-topping pizza visit:

brainly.com/question/371335

#SPJ9

6 0

2 years ago

∠ACB is inscribed in semicircle ACB of a circle with centre O then m∠ACB =

Zolol [24]

<h2>Answer:</h2>

[C] 90°.

<u>It is Because ∠ACB is formed by the diameter of the semicircle</u>.

<u>And we already know that, the angle formed by diameter measure 90° to the circle or semicircle</u>.

6 0

3 years ago

Read 2 more answers

Simplify 7t · s · 3rt.<br><br> 10rst<br> 10rst2<br> 21rst2

Fynjy0 [20]

Putting it like 7*t*s*3*r*t and multiplying like terms using the commutative property, we get 21*t²*s*r or 21rst²

3 0

4 years ago

Call an integer $n$ oddly powerful if there exist positive integers $a$ and $b$, where $b>1$, $b$ is odd, and $a^b = n$. How

azamat

Answer:

There are 16 oddly powerful integers less than 2010

Step-by-step explanation:

∵ b is an odd integer

∵ b > 1

∴ The first value of b is 3

∵ a is an integer

- We can use a = 1, 2, 3, ..........

∵ $a^{b}=n$

∵ n < 2010

- Let a = 1, 2, ............... 12 because 12³ is greatest integer < 2010

∵ 1³ = 1, 2³ = 8, 3³ = 27, 4³ = 64, 5³ = 125, 6³ = 216, 7³ = 343,

8³ = 512, 9³ = 729, 10³ = 1000, 11³ = 1331, 12³ = 1728

∴ There are 12 oddly powerful integers with b = 3

Now the second value of b is 5

$1^{5}=1$ but we took 1 before so we will start with 2

∵ $2^{5}=32$ , $3^{5}=243$ , $4^{5}=1024$

- $4^{5}$ is the greatest integer < 2010

∴ There are 3 oddly powerful integers with b = 5

Now the third value of b is 7

∵ $2^{7}=128$

- $2^{7}$ is the greatest integer < 2010

∴ There is 1 oddly powerful integers with b = 7

Now the fourth value of b is 9

∵ $2^{9}=512$

- $2^{9}$ is the greatest integer < 2010

- But we used 512 before

∴ There is no oddly powerful integers with b = 9

- 9 is the greatest value of b which makes $a^{b}$

∵ 12 + 3 + 1 = 16

∴ There are 16 oddly powerful integers less than 2010

5 0

3 years ago