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wel
3 years ago
8

Write an equivalent numeric expression using the distributive property. 4+28

Mathematics
2 answers:
Kobotan [32]3 years ago
6 0
You can divide the expression by 4
4(1+7)
bixtya [17]3 years ago
3 0
2(2+14) you just have to divide 4+28 by 2. 

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Can somebody help me solve
ikadub [295]

Answer:

x \leqslant  - 21

8 0
3 years ago
Solve the inequation 2x -3(3x-4)>_8​
svlad2 [7]

Answer:

x≤47

Step-by-step explanation:

2x−3(3x−4)≥8

Step 1: Simplify both sides of the inequality.

−7x+12≥8

Step 2: Subtract 12 from both sides.

−7x+12−12≥8−12

−7x≥−4

Step 3: Divide both sides by -7.

−7x−7≥−4−7x≤47

Answer:x≤47

8 0
3 years ago
Jordyn made some bracelets and sold them at a craft fair for 8$ each. She paid 50$ in materials and fees. Jordyns profit after t
Doss [256]

Answer:

45

Step-by-step explanation:

first take the $310 and add the $50 in profit and you get $360 divide that by $8 and you get 45

8 0
3 years ago
Solve for x, if a solution is extraneous identify in the final answer. thx :)
Fantom [35]

Answer:

x = 6 and x = 11.

Step-by-step explanation:

sqrt(x - 2) + 8 = x

sqrt(x - 2) = x - 8

(sqrt(x - 2))^2 = (x - 8)^2

x - 2 = x^2 - 16x + 64

x^2 - 16x + 64 = x - 2

x^2 - 17x + 66 = 0

We can use the discriminant to find whether there are solutions to the equation.

b^2 - 4ac; where a = 1, b = -17, and c = 66.

(-17)^2 - 4 * 1 * 66

= 289 - 264

= 25

Since the discriminant is positive, we know there are two valid solutions to the equation.

x^2 - 17x + 66 = 0

(x - 6)(x - 11) = 0

The solutions are when x - 6 = 0 and x - 11 = 0.

x - 6 = 0

x = 6

x - 11 = 0

x = 11

Hope this helps!

8 0
3 years ago
Read 2 more answers
An ellipse has a co-vertex at (–8, 9) and a foci at (4, 4). If the center of the ellipse is located below the given co-vertex, t
vovikov84 [41]

Answer:

Step-by-step explanation:

“the center of the ellipse is located below the given co-vertex”

Co-vertex and center are vertically aligned, so the ellipse is horizontal.

Equation for horizontal ellipse:

(x-h)²/a² + (y-k)²/b² = 1

with

a² ≥ b²

center (h,k)

vertices (h±a, k)

co-vertices (h, k±b)

foci (h±c,k), c² = a² -b²

One co-vertex is (-8,9), so h = -8.

One focus is (4,4), so k = 4.

Center (h,k) = (-8,4)

c = distance between center and focus = |-8 - 4| = 12

b = |9-k| = 5

a² = c² + b² = 169

(x+8)²/169 + (y-4)²/25 = 1

7 0
3 years ago
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