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Andreyy89
3 years ago
7

If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t − 16t2. Fi

nd the velocity when t = 1.
Mathematics
1 answer:
Andru [333]3 years ago
8 0
\bf y=42t-16t^2\implies \left. \cfrac{dy}{dt}=42-32t \right|_{t=1}\implies 42-32\implies 10
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