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3 years ago

Factor out the GCF 6x^3-9x^2-12x

Mathematics

2 answers:

Dafna11 [192]3 years ago

5 0

The GCF of the 3 terms is 3x.

The expression is equal to <u> 3x (2x² - 3x - 4)</u>

Olenka [21]3 years ago

3 0

$6x^3-9x^2-12x\\
first\ finding\ the\ GCF\ of\ all\ terms:\\\\
6: \ 1,2,3,6\\
9: \ 1,3,9\\
12: \ 1,3,4,6,12\\
GCF=3x\\
3x(\ \ \ )\\\\
Next\ divide\ each\ term\ of\ the\ original\
expression\ 6x^3-9x^2-12x\\
by\ GCF:\\\\
-6x^3:3x=-2x^2\\
-9x^2:3x=-3x\\
-12x:3x=-4\\\\
Answer:
3x(-2x^2-3x-4)$

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Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).

Mariulka [41]

Answer:

$\bigl(\frac{3}{2},-5\bigr)$

or in decimal form

$(1.5,-5)$

Step-by-step explanation:

The midpoint of the line with endpoints $(x_1,y_1)$ and $(x_2,y_2)$ is $\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)$ . just take the average between the points

so given the points (1,0) and (2,-10)

$x_1=1$

$y_1=0$

$x_2=2$

$y_2=-10$

the midpoint is found as follows:

$\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)$

$\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)$

$\bigl(\frac{3}{2},\frac{-10}{2}\bigr)$

$\bigl(\frac{3}{2},-5\bigr)$

or in decimal form

$(1.5,-5)$

7 0

3 years ago

Ill give you braindeath if you get this right

victus00 [196]

Answer:

The larger angle is 144 degrees and the smaller angle is 36 degrees

Step-by-step explanation:

Because this is a supplementary angle you have to find out what x is to solve this equation $2.4x+9.6x=180$

Because 2.4x and 9.6x are like terms we add them $2.4x+9.6x=12x$

So now to find x we divide 180 by 12 to get 15 $\frac{12x}{12} =\frac{180}{12}$

We replace the x with 15 $2.4(15)+9.6(15)=36+144$

We add 36 and 144 which equals 180

5 0

2 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!

vampirchik [111]

Plumber a = 60x
Plumber b = 40+55x
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2 years ago

A screening test for a certain disease is used in a large population of people of whom 1 in 1000 actually have the disease. Supp

sertanlavr [38]

Answer:

$P(D/T)=5.05*10^{-6}$

Step-by-step explanation:

Let's call D the event that a person has the disease, D' the event that a person doesn't have the disease and T the event that the person tests negative for the disease.

So, the probability P(D/T) that a randomly chosen person who tests negative for the disease actually has the disease is calculated as:

P(D/T) = P(D∩T)/P(T)

Where P(T) = P(D∩T) + P(D'∩T)

So, the probability P(D∩T) that a person has the disease and the person tests negative for the disease is equal to:

P(D∩T) = (1/1000)*(0.005) = 0.000005

Because 1/1000 is the probability that the person has the disease and 0.005 is the probability that the person tests negative given that the person has the disease.

At the same way, the probability P(D'∩T) that a person doesn't have the disease and the person tests negative for the disease is equal to:

P(D'∩T) = (999/1000)*(0.99) = 0.98901

Finally, P(T) and P(D/T) are equal to:

P(T) = 0.000005 + 0.98901 = 0.989015

$P(D/T) = 0.000005/0.989015 = 5.05*10^{-6}$

8 0

2 years ago

If A is (-2,6) and B is (4,-2), what is the midpoint of AB

sashaice [31]

Given two points:
A(x₁,y₁) and B(x₂,y₂) the midpoint would be:
M((x₁+x₂)/2 , (y₁+y₂)/2)
In this case:_
A(-2,6) and B(4,-2); the midpoint would be:
M((-2+4)/2 , (6-2)/2)=(1,2)

Answer: the midpoint of AB is (1,2)

4 0

3 years ago