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kirill115 [55]
2 years ago
10

The angle of Inclination from the base of skyscraper A to the top of skyscraper B is approximately 11.9°. If Skyscraper B is 142

4 feet tall, how far apart are the two skyscrapers? Assume
the bases of the two buildings are at the same elevation.
feet.
The distance from skyscraper A to skyscraper B is
(Round to two decimal places as needed.)
Mathematics
2 answers:
Verdich [7]2 years ago
7 0

Answer:

6757.36ft to 2dp

Step-by-step explanation:

For base distance there are different ways in trigonometry to find the base. For this finding we are given the height and opposite angle.

We can then calculate; using division 1424 /tan 11.9 =6757.36427ft

For slope we can find Sin(11.9°) x 1424 to find 293.63ft.

It shows, 293.63476 on the calculator so the answer is kept at 293.63ft= left to 2dp ( or 3524 inches) away

Naya [18.7K]2 years ago
5 0

Answer:

Step-by-step explanation:

Jajshvs

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Mrac [35]
First, you should substitute a, b, and c with -3, 9, and 4, so you get 4(-3(2)+9+4)

Next, following PEMDAS, you solve everything in the (,), leaving you with 4(7).

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3 years ago
Which of the following is a measurement of the space between two objects? A. Area B. Pounds C. Circumference D. Miles
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D, miles. Pounds would be weight. Circumference is the distance around a circle. Area is the amount of square units in an area.
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3 years ago
Which expressions would complete this equation so that it has infinitely many solutions?
andrezito [222]
The way I would do this is to distribute the original piece and get
8 + 16x -12, which is the same as 16x -4, so C is definitely one of the answers
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3 years ago
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olganol [36]

Answer:

73.8

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5 0
3 years ago
Transversal cuts parallel lines and at points X and Y respectively. The point nearest to C is X, and the point nearest to D is Y
hammer [34]

Answer:  The answer is (B) ∠SYD.


Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.

We are given four angles, out of which one should be chosen which is congruent to ∠CXP.

The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.

For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.

Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.

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∠CXP ≅ ∠SYD.

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3 years ago
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