The angle of Inclination from the base of skyscraper A to the top of skyscraper B is approximately 11.9°. If Skyscraper B is 142

Question

3 years ago

10

The angle of Inclination from the base of skyscraper A to the top of skyscraper B is approximately 11.9°. If Skyscraper B is 142

4 feet tall, how far apart are the two skyscrapers? Assume
the bases of the two buildings are at the same elevation.
feet.
The distance from skyscraper A to skyscraper B is
(Round to two decimal places as needed.)

Mathematics

2 answers:

Verdich [7] · Answer 1 · 2022-08-18T20:43:51+03:00

Answer:

6757.36ft to 2dp

Step-by-step explanation:

For base distance there are different ways in trigonometry to find the base. For this finding we are given the height and opposite angle.

We can then calculate; using division 1424 /tan 11.9 =6757.36427ft

For slope we can find Sin(11.9°) x 1424 to find 293.63ft.

It shows, 293.63476 on the calculator so the answer is kept at 293.63ft= left to 2dp ( or 3524 inches) away

Naya [18.7K] · Answer 2 · 2022-08-18T18:58:59+03:00

Naya [18.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

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