Find the value of this expression if x = 7 and y = 1 xy^2/-8
1 answer:
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Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to
we have
so
Simplify
-----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to
so
Multiply by 2 both sides
----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m
(7x + 4)(7x + 4) and (x – 9)(x – 9) are Perfect square trinomial. (5x + 3)(5x – 3) and (–3x – 6)(–3x + 6) shows the Difference of squares.
<h3>What is a perfect square?</h3>A perfect square is a number system that can be expressed as the
square of a given number from the same system.
The following are the answers
(5x + 3)(5x – 3) Difference of squares
(7x + 4)(7x + 4) is a Perfect square trinomial
(2x + 1)(x + 2) has Neither a difference of squares nor a perfect square trinomial.
(4x – 6)(x + 8) has Neither a difference of squares nor a perfect square trinomial.
(x – 9)(x – 9) is Perfect square trinomial
(–3x – 6)(–3x + 6) = Difference of squares.
Learn more about perfect square: