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Setler [38]
3 years ago
14

1. Suppose an arithmetic sequence has common difference 5,and the current

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer:

55

Step-by-step explanation:

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You read online that the probability of being dealt four‑of‑a‑kind in a five‑card poker hand is 1 / 4165. Explain carefully what
Lapatulllka [165]

Answer:

There is about 4,164/4,165 chances of not getting getting a four of a kind. So, it is extremely unlikely or even borderline impossible in that situation to get a four of a kind.

<u>But in the long run, it can be increased only if you keep drawing.  So, the awnser would have to be. D  </u>

Step-by-step explanation:

A. It does mean that if you are dealt 4165 five‑card poker hands, one will be four‑of‑a‑kind.

B.  It does not mean that all will be four‑of‑a‑kind. The probability is actually saying that only on the 4165 the poker hand will you get a four‑of‑a‑kind, not just on any of the 4165 poker hands.

C. The probability is actually saying that in the long run, with a large number of five‑card poker hands, the fraction in which you will be dealt a four‑of‑a‑kind is 1 / 4165.

D. The chance you will be dealt four‑of‑a‑kind is 1 / 4165 only on the first hand. This chance will then increase with each new hand you are dealt until you eventually win

6 0
2 years ago
Please help with this Math Question...
Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 |   1   4   7   6

   <u>|   ↓  -2  -4  -6</u>

       1    2    3   0 ← remainder is 0 so x = -2 is a root  ⇒  (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}

x=\dfrac{-2\pm\sqrt{4-12} }{2}

x=\dfrac{-2\pm\sqrt{-8} }{2}

x=\dfrac{-2\pm2i\sqrt{2}}{2}

x = -1 \pm i\sqrt{2}

x = -1 + i\sqrt{2}       x = -1 - i\sqrt{2}

x - (-1 + i\sqrt{2})=0       x - (-1 - i\sqrt{2})=0

The factors are:

(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]




5 0
2 years ago
If 101! = (99!)x, then x = ?
beks73 [17]
99!x=101!\ \ \ /:99!\\\\x=\frac{101!}{99!}\\\\x=\frac{99!\cdot100\cdot101}{99!}\\\\x=100\cdot101\\\\x=10\ 100
5 0
3 years ago
The value of y varies directly with x, and y = 18 when x = 12. find y when x = 132.
sveta [45]
This would be 198 because 12 times 1.5 equals 18 so when you multiply 132 by 1.5 you get 198
4 0
3 years ago
I need help fast. 8th grade multiple question. (I added photos)
n200080 [17]

Answer:

C is the answer

Step-by-step explanation:

5 0
3 years ago
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