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3 years ago

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a rectangualr garden is to be enclosed usinf two different types of fencinf. one side of the garden boarders a road and the fenc

ing for this side costs $25 per foot. The fencinf for the other sides costs $10 per foot

1 answer:

murzikaleks [220]3 years ago

8 0

Answer: 250

Step-by-step explanation:

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.Rahul and his wife work in Mohan's farm. The Government has declared that the farm workers should be paid Rs. 71 for a day's wo

Snowcat [4.5K]

Answer:

Rs. 5500

Step-by-step explanation:

The government has declared that farm workers should be paid Rs. 71 for a day's work

The landlord Mohan pays Rahul Rs. 60 and pays Rs. 55 to his wife

Rahul works for 55 days

= 60 × 55

= Rs. 3,300

His wife works for 40 days

= 55 ×40

= Rs. 2,200

Therefore the total amount of money earned together can be calculated as follows

= 3300 + 2200

= Rs. 5500

Hence they will earn Rs. 5500 together

7 0

3 years ago

I have no idea how to solve this. please help?

matrenka [14]

I believe it’s c

π=C/2r

8 0

2 years ago

How can I fin the remainder to 8,595 ÷ 24?

Drupady [299]

Answer:

358 and remainder of 3

Step-by-step explanation:

1. Divide it like any other problem

24 goes into 85, 3 times with 13 left over
Bring down the 9 and 24 goes into 139, 5 times with 19 left over
Then bring down the 5 and 24 goes inside 195, 8 times with 3 left over

So your remainder would be 3

Hope this helps

8 0

3 years ago

What is the answer to 15% of 18Kg

Maurinko [17]

Answer:

27/10, or 2 7/10 kg

Step-by-step explanation:

We first have the expression 15/100*18, which simplifies to 3/20*18. If we multiply and simplify, we get 27/10, or 2 7/10

7 0

2 years ago

Read 2 more answers

What is the sum of the distances of R to Q and P to Q?

Shalnov [3]

The sum of the distances of R to Q and P to Q is 9 units.

Solution:

Given points are P(–3, 6), Q(3, 6) and R(3, 3).

Distance between two points formula:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance from R to Q:

Here $x_1=3, y_1=3, x_2=3, y_2=6$

Substitute these in the given formula, we get

Distance = $\sqrt{(3-3)^2+(6-3)^2}$

$=\sqrt{0+9}$

= 3 units

Distance from R to Q is 3 units.

Distance from P to Q:

Here $x_1=-3, y_1=6, x_2=3, y_2=6$

Substitute these in the given formula, we get

Distance = $\sqrt{(3-(-3))^2+(6-6)^2}$

$=\sqrt{36+0}$

= 6 units

Distance from P to Q is 6 units.

Sum of the distances = 3 + 6 = 9 units

Hence the sum of the distances of R to Q and P to Q is 9 units.

4 0

3 years ago