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Effectus [21]
3 years ago
13

a rectangualr garden is to be enclosed usinf two different types of fencinf. one side of the garden boarders a road and the fenc

ing for this side costs $25 per foot. The fencinf for the other sides costs $10 per foot
Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer: 250

Step-by-step explanation:

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It takes a jet 2 hours to fly 1,100 miles. At this rate, how far does it fly in 8 hours?
Anuta_ua [19.1K]

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4400 miles

Step-by-step explanation:

In 1 hour it can fly 1100/2 = 550 miles

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2 years ago
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Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two​ bakeries' specialty pi
DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>

Step-by-step explanation:

The given data are;

Bakery A

\overline x_1<em> </em>= 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

\overline x_2<em> </em>= 1,711 cal

s₂ = 192 cal

n₂ = 10

\left (\bar{x}_1-\bar{x}_{2}  \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, t_c = 1.706

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469

\hat \sigma ≈ 178

Therefore, we get;

\left (1,880-1,711  \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711  \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}

Which gives;

169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0
3 years ago
Consider the expression 3 * 2 ^ 2 &lt; 16 + 5 andalso 100 / 10 * 2 &gt; 15 - 3. which operation is performed second
BartSMP [9]
3 * 2 ^ 2 < 16 + 5
should be performed in the order PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction)/
Therefore, obtain
3 * 2 ^ 2 < 16 + 5
3 * 4 < 16 + 5           Exponentiation first
12 < 16 + 5               Multiplication second

Similarly, obtain
100 / 10 * 2 > 15 - 3
100 / 20 > 15 - 3      Multip[lication first
5 > 15 - 3                  Division second

5 0
3 years ago
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