If you graph the coordinate (3,4) and then apply the slope (7 up / 1 down) , you will end up passing through the point (0,-17) on the y line. The point the line passes on the y line would be the y intercept.

Once you have all the necessary information, you put it into a y=mx+b form. m being the rate or slope, and b being the y-intercept.

8 0

3 years ago

Indicate the equation of the line, in standard form, that passes through (2, -4) and has a slope of 3/5. Enter your answer into

yulyashka [42]

The equation of the line is $y = (3/5)x + 26/5$

<u>Step-by-step explanation:</u>

The line passes through the point (2,-4).
The line has the slope of 3/5.

To find the equation of the line passing through a point and given its slope, the slope-intercept form is used to find its equation.

<u>The equation of the line when a point and slope is given :</u>

⇒ $(y-y1) = m(x-x1)$

where,

m is the slope of the line.
(x1,y1) is the point (2.-4) in which the line passes through.

Therefore, the equation of the line can be framed by,

⇒ $(y-(-4)) = 3/5 (x-2)$

⇒ $(y+4) = 3/5(x-2)$

Take the denominator 5 to the left side of the equation.

⇒ $5(y+4) = 3(x-2)$

Now, multiply the number outside the bracket to each term inside the bracket.

⇒ $5y+20 = 3x -6$

⇒ $5y = 3x-26$

Divide by 5 on both sides of the equation,

⇒ $y = (3/5)x + 26/5$

Therefore, the equation of the line is $y = (3/5)x + 26/5$

4 0

3 years ago

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