Answer:
Answer of 17 is ㏒(
+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is x = -㏒12/㏒8 and Answer of 39 is x = 5
Step-by-step explanation:
17. ㏒x + ㏒(x+15)
Using property ㏒a + ㏒b = ㏒a×b
∴ ㏒x + ㏒(x+15)
㏒x×(x+15)
㏒(
+15x)
The answer is ㏒(
+15x)
33. 2^(x-5) = 8
2^(x-5) = 2^3
Using property 2^a = 2^b
Then a = b
∴x-5 = 3
x = 8
The answer is x = 8
35. 2^x = 10
Taking log on both sides gives
㏒2^x = ㏒10
x×㏒2 = ㏒10
x = ㏒10/㏒2
The answer is x = ㏒10/㏒2
37. 8^-x = 12
Taking log on both sides gives
㏒8^-x = ㏒12
-x×㏒8 = ㏒12
x = -㏒12/㏒8
The answer is x = -㏒12/㏒8
39. 5(2^3 × x) = 8
5(8×x) = 8
x = 5
The answer is x=5
Answer:

Step-by-step explanation:


The answer is 3/4 and it was already simplified
9514 1404 393
Answer:
a9 = -8 +9(9 -1)
Step-by-step explanation:
The given sequence has a common difference of 1-(-8) = 10-1 = 9, and a first term of -8. The formula for the n-th term of such an arithmetic sequence is ...
an = a1 +d(n -1) . . . . . first term a1, common difference d
For the parameter of this sequence, a1=-8 and d=9, the n-th term is ...
an = -8 +9(n -1) . . . . formula for the n-th term
__
Then the formula for the 9th term is ...
a9 = -8 +9(9 -1)