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ohaa [14]
3 years ago
10

Pls help (I did most of the page...)

Mathematics
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

the tripled recipe of peaches is 2 or 6/3

the tripled amount of rhubarb would be 21/2 or 10\frac{1}{2}

Step-by-step explanation:

for the first part, just multiply the top number (2) by 3. (that would be 6)

then, divide that by the bottom number (3).

6/3 = 2.

for the second part, you need to convert the mixed number to an improper fraction.

3\frac{1}{2} as an improper fraction is \frac{7}{2}

now, multiply the top number (7) by 3. (that would be 21)

then. divide that by the bottom number. (2)

21/2 = 10\frac{1}{2}

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How to solve this? ​
nevsk [136]

Answer:

Answer of 17 is ㏒(x^{2}+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is  x = -㏒12/㏒8 and Answer of 39 is x = 5

Step-by-step explanation:

17. ㏒x + ㏒(x+15)

     Using property ㏒a + ㏒b = ㏒a×b

     ∴ ㏒x + ㏒(x+15)

        ㏒x×(x+15)

        ㏒(x^{2}+15x)

        The answer is ㏒(x^{2}+15x)

33. 2^(x-5) = 8

     2^(x-5) = 2^3

      Using property 2^a = 2^b

      Then a = b

     ∴x-5 = 3

       x = 8

      The answer is x = 8

35. 2^x = 10

    Taking log on both sides gives

     ㏒2^x = ㏒10

     x×㏒2 = ㏒10

     x = ㏒10/㏒2

    The answer is x = ㏒10/㏒2

37. 8^-x = 12

    Taking log on both sides gives

     ㏒8^-x = ㏒12

     -x×㏒8 = ㏒12

      x = -㏒12/㏒8

    The answer is  x = -㏒12/㏒8

39. 5(2^3 × x) = 8

      5(8×x) = 8

      x = 5

    The answer is x=5

 

5 0
3 years ago
Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)​
Leviafan [203]

Answer:

\huge\boxed{x=1\ \vee\ x=2}

Step-by-step explanation:

3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}

\text{We return to substitution:}\\\\3^x=t\\\\3^x=3\ \vee\ 3^x=9\\\\3^x=3^1\ \vee\ 3^x=3^2\\\\\boxed{x=1}\ \vee\ \boxed{x=2}

4 0
3 years ago
Find and simplify the quotient 2/3 divided by 8/9
Anuta_ua [19.1K]
The answer is 3/4 and it was already simplified
8 0
3 years ago
-8, 1, 10...<br> n<br> What is a formula for the ninth term of the given sequence
krek1111 [17]

9514 1404 393

Answer:

  a9 = -8 +9(9 -1)

Step-by-step explanation:

The given sequence has a common difference of 1-(-8) = 10-1 = 9, and a first term of -8. The formula for the n-th term of such an arithmetic sequence is ...

  an = a1 +d(n -1) . . . . . first term a1, common difference d

For the parameter of this sequence, a1=-8 and d=9, the n-th term is ...

  an = -8 +9(n -1) . . . . formula for the n-th term

__

Then the formula for the 9th term is ...

  a9 = -8 +9(9 -1)

6 0
3 years ago
Solue for a<br> d3a=b<br> 3<br> Please help
laiz [17]

Answer:

{d}^{3} a = b \\   \frac{ {d}^{3}a }{ {d}^{3} }  =  \frac{b}{ {d}^{3} }  \\  \\ { \boxed{ \boxed{a =  \frac{b}{ {d}^{3} } }}}

5 0
3 years ago
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