All categories

3 years ago

12points I will give pls help

Mathematics

1 answer:

Lady_Fox [76]3 years ago

8 0

Answer:

$\\ m=3$

Step-by-step explanation:

$\\ m=\frac{y_2-y_1}{x_2-x_1}\\\\ m=\frac{2-(-1)}{0-(-1)}\\\\ m=\frac{2+1}{1}\\\\ m=3$

Hope this helps you. Have a nice night.

You might be interested in

ZP bisects ∠OZQ so that ∠OZP = 8x – 9 and ∠PZQ = 5x + 18. Find the value of x, and the measure of each angle. You must show all

Assoli18 [71]

<span>x = 9 Since ZP bisects â OZQ, that means that the measurements for â OZP and â PZQ are the same. So create an equation with their respective values set to each other. 8x - 9 = 5x + 18 Now solve for x 8x - 9 = 5x + 18 Subtract 5x from both sides 3x - 9 = 18 Add 9 to both sides 3x = 27 Divide both sides by 3 x = 9</span>

6 0

3 years ago

What is “1 more than the product of a number (n) and -8” as an algebraic expression?

3241004551 [841]

Answer:

-8n+1

Step-by-step explanation:

the word product indicates multiplication and it says that the product is between n and -8 so we are multiplying -8 and n. 1 more indicates addition so we are adding 1 to the product of -8n.

5 0

3 years ago

In the figure below, points M, P, H, J, and K lie in plane Z.

marishachu [46]

Answers:

(a) LN
(b) PHJ
(c) K
(d) HK

===================================================

Explanation:

Part (a)

Lines LN and PN have the point N in common. This is the intersection point.

-----------------

Part (b)

To name a plane, pick any three non-collinear points that are inside it. We cannot pick points H, J, K together because infinitely many planes pass through it. Imagine the piece of flat paper able to rotate around this axis (like a propeller). Having the points not all on the same line guarantees we form exactly one unique plane.

I'll pick the non-collinear points P, H and J to get the name Plane PHJ. Other answers are possible.

------------------

Part (c)

Points H, J and K are collinear as they are on the same line. Pick either H or K to fill out the answer box. I'll go with point K

------------------

Part (d)

Point P and line HK are coplanar. They exist in the same flat plane, or on the same sheet of flat paper together.

We can think of that flat plane as the ground level while something like point N is underground somewhere. So point N and anything on that ground plane wouldn't be coplanar.

Note: there are other possible names for line HK such as line JH or line JK. The order doesn't matter when it comes to naming lines.

4 0

3 years ago

Consider the question of whether the home team wins more than half of its games in the National Basketball Association. Suppose

spayn [35]

Answer:

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$