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monitta
3 years ago
9

What is the perimeter of a square with an area of 64 m2?

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0
If the area is 64 of a square that mean its 8X8 so your answer would be 32 since it has 4 sides 
(0-0) Hope it helps have a nice day

Alenkasestr [34]3 years ago
7 0
Each side would be = square root of 64 which is  8m

Perimeter = 8 * 4 = 32 m.
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How many cubes that measure 2 inches by 2 inches by 2 inches would fit inside a cube that measures 10 inches by 10 inches by 10
11111nata11111 [884]
25, because a cube that is 10x10 would have an area of 100. and the cubes that are 2x2 would have an area of 4. so you take 100 and divide it by 4. answer is 25.
5 0
3 years ago
Suponha que uma variável assume os valores: 11 – 8 – 7 – a – 16 – 10 Determine a de modo que a média aritmética seja igual 11.
Elenna [48]

Answer:

a = 14  

Step-by-step explanation:

The mean is the sum of the values divided by the number of values.

\begin{array}{rcl}\text{Mean}&= &\dfrac{11 + 8 + 7 + a + 16 + 10}{6}\\\\\dfrac{52 + a}{6}& = & 11\\52 + a & = & 66\\a & = & 66 - 52\\& = & \mathbf{14}\\\end{array}

4 0
4 years ago
The area of a certain desert desert one is five times the area of another desert desert 2 if the sum of their areas is 24, 000,
sweet-ann [11.9K]

4,000,000 and 20,000,000 miles²

let x be the area of one desert then 5x is the area of the other

sum = x + 5x = 24,000,000

6x = 24,000,000

divide both sides by 6

x = 4,000,000

one desert is 4,000,000 miles²

and the other is (5 × 4,000,000)= 20,000,000 miles²


8 0
4 years ago
Read 2 more answers
Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh
Yakvenalex [24]
Let ABC be a triangle in the 3rd quadrant, right-angled at B. 
 So, AB-> Perpendicular BC -> Base AC -> Hypotenuse. 
Given: sinθ=-3/5 cosecθ=-5/3 
 According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
 Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
 Since sinθ=Perpendicular/Hypotenuse ,
 AC=5 and AB=3
 Substituting these values in equation (1)
 
〖BC〗^2=〖AC〗^2-〖AB〗^2

 ă€–BC〗^2=5^2-3^2
 

 ă€–BC〗^2=25-9

 ă€–BC〗^2=16

 BC=4 units

 Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
 So,cosθ=Base/Hypotenuse Cosθ=-4/5 
 secθ=Hypotnuse/Base secθ=-5/4 
 tanθ=Perpendicular/Base tanθ=3/4  
 cotθ=Base/Perpendicular cotθ=4/3
4 0
3 years ago
Given the box plot, will the mean or the median provide a better description of the center?
ohaa [14]

Answer:

The mean, because the data distribution is symmetrical.

Step-by-step explanation:

Without even knowing the mean or median this can be solved. The data isn't skewed to the left nor right, so it is symmetrical. The mean is the central value of numbers so it should represent the center well.

5 0
3 years ago
Read 2 more answers
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