The angle between the two tangents drawn from an external point to a circle and the angle subtended by the line segment joining the points of the contact at the Centre are supplymentary,
So,
15.) let the unknown angle be x
=》x + 55° = 180°
=》x = 180° - 55°
=》
![\boxed{x = 125°}](https://tex.z-dn.net/?f=%20%5Cboxed%7Bx%20%3D%20125%C2%B0%7D)
16. let the unknown angle be n
=》n + 80° = 180°
=》n = 180° - 80°
=》
![\boxed{n = 100°}](https://tex.z-dn.net/?f=%20%5Cboxed%7Bn%20%3D%20100%C2%B0%7D)
Answer:
3.9375
Step-by-step explanation:
So, the slope is 2 for each of the points. Now, you plug it into y=mx+bSo, you get, y=2x+b
To find b, you choose any pair of x and y values.-5=-22+bb=17
We observe that the relationship between the variables is linear.
Therefore, we look for an equation of the form:
![b = m * a + b ' ](https://tex.z-dn.net/?f=b%20%3D%20m%20%2A%20a%20%2B%20b%20%27%0A)
Where,
m: slope of the line
b ': intersection with the y axis
a: independent variable
b: dependent variable
The value of b 'occurs when a = 0.
We have then:
![b '= -10 ](https://tex.z-dn.net/?f=b%20%27%3D%20-10%0A)
(See table)
Then, the value of the slope is found using the following formula:
![m = \frac{b2-b1}{a2-a1}](https://tex.z-dn.net/?f=m%20%3D%20%20%5Cfrac%7Bb2-b1%7D%7Ba2-a1%7D%20)
Substituting values:
![m = \frac{-7-(-10)}{1-0}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-7-%28-10%29%7D%7B1-0%7D%20)
Rewriting:
![m = 3](https://tex.z-dn.net/?f=m%20%3D%203%20)
Thus, the linear equation is:
![b = 3*a-10](https://tex.z-dn.net/?f=b%20%3D%203%2Aa-10%20)
Rewriting:
Answer:
The equation is:
C.) 3a-b=10
Answer:
ax+by =c
Step-by-step explanation:
where a and b are the coifficients of the x and y variable respectively