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Alenkinab [10]
3 years ago
15

Which represents the solution set of the inequality 5x-9 less than or equal to 21

Mathematics
2 answers:
kiruha [24]3 years ago
5 0
The answer is x is less than or equal to 6
Hope this helped :)
Viktor [21]3 years ago
3 0
5x - 9 < 21
5x < 21 + 9
5x < 30
x < 30/5
x < 6...so x is anything less then 6
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A simplified model of the human blood-type system has four blood types: A, B, AB, and O. There are two antigens, anti-A and anti
dexar [7]

Answer: Blood type will be A when event "A" happened and event "B" did not happen. Blood type will be B when event "A" did not happened and event "B" happened. Blood type will be AB when both events happened and blood type will be O when both events did not happen.

Step-by-step explanation:

S={AntiA reacts; AntiA does not react; AntiB reacts; AntiB does not react}

If AntiA reacts and AntiB reacts = AB (A∩B)

If AntiA does not react and AntiB does not react= O (A'∩B')

If AntiA reacts and AntiB does not react= A (A∩B')

If AntiA does not react and AntiB reacts= B (A'∩B)

4 0
4 years ago
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Her grandma will be there 40 minutes early. If you add the hours first, then it makes it 6:35. Add the 50 minutes, 7:25 is the arrival time.

6 0
4 years ago
Solve to find x and y in the diagram.
lesantik [10]

15x = 90

   x = 6


5(6) + 12y = 90

30 + 12y = 90

12y = 60

  y = 5

Answer: 3rd option

x =6, y = 5

5 0
4 years ago
When 8 is added to the number that is produced by doubling the number x, the result is equal to 8 times the number that is 5 les
pantera1 [17]
2x+8 = 8(x-5)
expand the rhs to get
2x+8 = 8x-40
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x = 48/6
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4 0
3 years ago
Read 2 more answers
Six cell phones weigh 46.2 ounces. Fourteen cell phones weigh 107.8 ounces. What is the unit rate or constant of proportionality
iris [78.8K]

<u><em>Answer:</em></u>

<u><em>Well first we must see if they are proportional. </em></u>

<u><em> </em></u>

<u><em>46.2/6 = 10.7.8/14 </em></u>

<u><em>7.7 = 7.7 </em></u>

<u><em> </em></u>

<u><em>They are proportional. The rate of proportion is 7.7 ounces per cellphone. Hope this helps! </em></u>

<u><em /></u>

<u><em>Step-by-step explanation:</em></u>

8 0
3 years ago
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