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3 years ago

13

Paul bought a student discount card for the bus. The card allows him to buy daily bus passes for $1.60. After one month, Paul bo

ught 23 passes and spent a total of $42.80. How much did he spend on the student discount card?

1 answer:

Annette [7]3 years ago

6 0

Paul spent $6 on the student discount card. 23 times 1.60 equals 36.80. Subtract that from 42.80 and you get 6

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Find the equation of the line thatcpasses through (3, 1) and is parallel to y=1-2x.

Anna11 [10]

Slope of y=1-2x is -2
Using point intercept form:
y-1=-2(x-3)
y-1=-2x+6
y=-2x+7

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2 years ago

g On any day, the probability of rain is 0.3. The occurrence of rain on any day is independent of the occurrence of rain on any

Ksju [112]

Answer:

0.249579

Step-by-step explanation:

P(rain) = 0.3

P(no rain) = 1 - 0.3 = 0.7

The event of rain falling a second time within the next 5 days is possible in these ways

1. Rain on days 1 and 2

2. Rain on days 1 and 3; none on day 2

3. Rain on days 1 and 4; none on days 2 and 3

4. Rain on days 1 and 5; none on days 2, 3 and 4

5. Rain on days 1 and 6; none on day 2, 3, 4 and 5

$P(\text{second rain within 5 days}) = 0.3^2+0.3^2\times0.7+0.3^2\times0.7^2+0.3^2\times0.7^3+0.3^2\times0.7^4 = 0.3^2(1+0.7+0.7^2+0.7^3+0.7^4)= 0.09\times2.7731=0.249579$

5 0

3 years ago

Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are

Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

7 0

3 years ago

I need help Please!

Pachacha [2.7K]

Answer:

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Step-by-step explanation:

7 0

3 years ago

2) 83,97,85,84,96, 80,80,87,91<br> Mean median and mode

marusya05 [52]

$\text {Hi! Let's Solve this Problem!}$

$\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}$

$\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}$

$\underline {\text {Mean}}$

$\text {To Find the Mean you must Add all the Numbers then Divide.}$

$\text {Add:}$ $\text 80+80+83+84+85+87+91+96+97=\fbox {783}}$

$\text {Divide:}$ $\text {783/9=}$

$\text {The Mean Is:}$

$\fbox {87}$

$\underline {\text Median}}$

$\text {To find the Median you find the number that's in the middle of the set.}$

$\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}$

$\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}$

$\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87}$ $\text {it shows that 85 is left in the middle.}$

$\text {The Median Is:}$

$\fbox {85}$

$\underline {\text {Mode}}$

$\text {Finding the Mode means finding the number}$ $\text { that shows the most in the number set given.}$

$\text {Since 80 is the number that is showing more than any other number}$ $\text {this tells us that 80 is our Mode.}$

$\text {The Mode Is:}$

$\fbox {80}$

$\text {Best of Luck!}$

4 0

3 years ago