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Illusion [34]
3 years ago
7

A central angle, thata, of a circle with radius 16 inches intercepts an arc of 19.36 inches. Find thata.

Mathematics
2 answers:
kaheart [24]3 years ago
5 0
Theta*
\theta=\frac{19.36}{16}=1.21 radians.
Setler [38]3 years ago
3 0

Answer:

1.21 would be the answer i think

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if a runner finishes the 26.2. mille race in 4 hours and 37 mins and Wilson kipping finish in 4 minutes and 43 seconds per mile
Neporo4naja [7]

Answer

a) Wilson Kipsang is 7.046 miles per hour faster than the average runner.

Solution is presented below under Explanation.

b) Wilson Kipsang is 2.24 times faster than the average runner.

c) When the average runner is at mile 6, Kipsang will be at mile 13.45.

d) Kipsang's record time = 2 hours, 3 minutes, 34.6 seconds

Explanation

To solve this, we will calculate the speed of the average runner and then the speed of Wilson Kipsang

Speed = (Distance/Time)

For the average runner

Distance = 26.2 miles

Time = 4 hours 37 mins = 4 hours + (37/60) = 4.617 hours

Speed = (Distance/Time)

Speed = (26.2/4.617)

Speed = 5.675 miles per hour

For Wilson Kipsang

Distance = 1 mile

Time = 4 minutes 43 seconds = (4/60) + (43/3600) = 0.0667 + 0.01194 = 0.0786 hour

Speed = (Distance/Time)

Speed = (1/0.0786) = 12.721 miles per hour

So, now, we are asked to find how much faster than the average runner is Wilson Kipsang

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

Wilson Kipsang is faster than the average runner by

(12.721 - 5.676) = 7.046 miles per hour

b) We are asked to find how many times faster than the average runner Wilson Kipsang is.

Let the number of times he is faster than the average runner be x

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

(5.675) (x) = (12.721)

Divide both sides by 5.675

x = (12.721/5.675)

x = 2.24 times

c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

Speed = (Distance/Time)

By cross multiplying, we see that

Time = (Distance/Speed)

For the average runner

Distance = 6 miles

Speed = 5.675 miles per hour

Time = (Distance/Speed)

Time = (6/5.675) = 1.057 hours

For Wilson Kipsang,

Speed = (Distance/Time)

By cross multiplying

Distance = (Speed) (Time)

Speed = 12.721 miles per hour

Time = 1.057 hours

Distance = (Speed) (Time)

Distance = (12.721) (1.057)

Distance = 13.45 miles

d) We were told that for Kipsang

1 mile = 4 minutes 43 seconds

26.2 miles = 26.2 (4 minutes 43 seconds)

26.2 miles = 26.2 (283 seconds) = 7414.6 seconds

We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

4 0
1 year ago
Solve 5p(2p - 3)(p + 7) = 0.<br> p=___, p=____, p=_____
Luba_88 [7]

Answer:

5p(2p-3)(p+7)=0

10p-15 p +7 =0

10p+p=0+15-7

11p =8

11p=8

p=8/11

5 0
2 years ago
PLEASE ANSWER ASAP! *PICTURE ATTACHED*
spin [16.1K]

Answer:

1) vertical line test

2) y=x

3)x

4)domain

7 0
3 years ago
What is the simplified expression for the expression below? 4(3x – 2) + 6x(2 – 1) 24x – 3 18x – 8 18x – 7 24x – 14
kvasek [131]

Answer:

Option b 18x-8 is correct answer.

Step-by-step explanation:

We need to simplify the expression 4(3x – 2) + 6x(2 – 1) and find the result.

Solving:

= 4(3x – 2) + 6x(2 – 1)

Multiplying terms with values in the bracket.

= 12x - 8 + 12x -6x

Adding like terms

= 12x + 12x - 6x -8

= 24x -6x -8

= 18x -8

So, Option b 18x-8 is correct answer.

6 0
3 years ago
Read 2 more answers
Joe is training for a race in 30 days. He needs to run a total of 135 miles. How many miles will joe need to run each day to be
marin [14]
He needs to run 4.5 miles each day.
4 0
3 years ago
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