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Illusion [34]
3 years ago
7

A central angle, thata, of a circle with radius 16 inches intercepts an arc of 19.36 inches. Find thata.

Mathematics
2 answers:
kaheart [24]3 years ago
5 0
Theta*
\theta=\frac{19.36}{16}=1.21 radians.
Setler [38]3 years ago
3 0

Answer:

1.21 would be the answer i think

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For a school play, 739 tickets valued at $857 were sold. Some cost $1 and others cost a $1.50. How many $1 tickets were sold?
balu736 [363]

Answer:

503 $1 tickets sold.

Step-by-step explanation:

Use two equations  

Let x = number of $1 tickets sold  

Let y = number of $1.50 tickets sold  

x + y = 739  

1x + (1.5)y = 857  

First equation ==> y = 739 - x  

Plug this into the second equation  

x + (1.5)(739 - x) = 857  

x + 1108.5 - 1.5x = 857  

- 0.5x = -251.5  

x = 503  

There were 503 $1 tickets sold.  

To find the number of $1.50 tickets, just plug this value of x into either one of the equations.  

(503) + y = 739       (739 - 503 = 236)

y = 236  

There were 236 $1.50 tickets sold.

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3 years ago
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11Alexandr11 [23.1K]

Answer:

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5 0
3 years ago
Find the average of these numbers to the nearest whole number. 516,497,501,528,476
defon

516+497+501+528+476= 2518

2518/5= 503.6

round up to 504

5 0
3 years ago
does somebody knows how to do this one?
vlada-n [284]

Answer:

Step-by-step explanation:

To find the area subtract the area of the semicircle from the area of the rectangle.

Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.

The area of rectangle is:

⇒ A = lw

⇒ A = (14)(8)

⇒ A = 112cm^{2}

The area of the semicircle;

⇒ A = \frac{1}{2}\pi r^{2}

⇒ A = \frac{1}{2}\pi (7)^{2}

*Note here that the radius is half the diameter, so it is 7cm, not 14cm

⇒ A = 76.97cm^{2}

Finally subtract the two areas;

⇒ A = 112 - 76.97

⇒ A = 35.03cm^{2}

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2 years ago
Select each transformation that carries a square onto itself. <br> please i need help :(
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Need points baggage haha ha she s s s s s s when’s she sub dbhd she s sus did
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