-7^-2does anyone know ?
2 answers:
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Answer:
and
Step-by-step explanation:
Given
Bisector: CD
of Line AB
Required
Apply Pythagoras Theorem
From the question, CD bisects AB and it bisects it at D.
The relationship between AB and CD is given by the attachment
Considering ACD
From the attachment, we have that:
By Pythagoras Theorem, we have
Considering CBD
From the attachment, we have that:
By Pythagoras Theorem, we have:
If we consider "a" as the edge length, and "D" the cube's diagonal, we have that the square cube's diagonal is equal to the edge length's square plus the side diagonal (d) square (Pythagoras theorem)
a² + d² = D²
And since:
d² = a² + a²
Clearing a, we have:
a² = D²-d²
<span>a² = D²-2a²
</span><span>3a² = D²
</span>a = √(<span>D²/3)
</span>
Surface area is equal to 6·a², so the surface area will be 6·(D²/3) = 2D²
The volume is a³, so the volume will be √(D²/3)³ = √(
<span>/3</span>³<span>) = D</span>³/√27
a² + d² = D²
And since:
d² = a² + a²
Clearing a, we have:
a² = D²-d²
<span>a² = D²-2a²
</span><span>3a² = D²
</span>a = √(<span>D²/3)
</span>
Surface area is equal to 6·a², so the surface area will be 6·(D²/3) = 2D²
The volume is a³, so the volume will be √(D²/3)³ = √(
Step-by-step explanation: