N = 33 and m = 6 substitute in the values in place of the variables to get 33 - 5*(6). distribute the five to get 33 - 30 =3. the answer is three
Answer: A. x= 5"
Step-by-step explanation:
ORIGINAL/NEW = 11"/7" = 8.5"/x
x = 7" x 8.5"/11" = 59.5"/11 = 5.409 ≅ 5.41"
If we wanted to keep most of the engraving, we would adjust the larger dimension, but we have been asked to adjust one dimension to 5", since it is said that C. x = 5.41 is incorrect
Then we will adjust the minor dimension to 5"
ORIGINAL/NEW = 11"/y = 8.5"/5"
y= 11" x 5"/8.5" = 6.47"
Then the new dimensions of the paper are 6.47" x 5" to fit an 7" x 5" frame
Answer: A. x= 5"
Answer: Am thinking it is B because am only 11 and I don't know if this is right. Hope this helps, or not...
Step-by-step explanation:
Let K and T be the speeds of Kirk and Thor respectively.
Note the standard definition that d=vt, distance equals velocity times time.
t=d/v
For Kirk, t=525/(T+5)
For Thor, t=490/T
Since we are told that they have traveled the same amount of time we can say t=t which leaves us:
525/(T+5)=490/T multiply both sides by T
525T/(T+5)=490 multiply both sides by T+5
525T=490T+2450 subtract 490T from both sides
35T=2450 divide both sides by 35
T=70
So Thor's average speed is 70kph, since K=T+5
K=75kph
So Kirk's average speed is 75kph