writing an equation of a line given its slope and y-intercept. write an equation in slope-intercept form for the line with slope
1 answer:
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Answer:
Please, find the image with the diagram of the lines corresponding to this question:
The answers are:
- Equation: m ∠ DCE = 180º - x
- Value of x = 60º
Explanation:
First question:
You must use the fact that the angles DCE and BCD are adjacent angles, because they share the vertex (C) and have a common side (CD).
Thus, as a first fact, the measure of the angle BCE is equal to the sum of the measures of the angles BCD and DCE.
On the other hand, BE is a straight line, thus the measure of angle BCE is 180º.
Hence, you can write:
- m ∠ DCE + m ∠ DCB = 180º
- m ∠ DCE + x = 180º
- m ∠ DCE = 180º - x
Second question:
Solve for x:
- Given: m ∠ DCE = 180º - x
- Add x to both sides: m ∠ DCE + x = 180º
- Subtract m ∠ DCE from both sides: x = 180º - m ∠DCE
Substitute m ∠DCE with 120º:
- x = 180º - 120º = 60º
Hence, for m ∠DCE = 120º, x = 60º.
