All your answers look good!
D/13>-3
You have to multiply 13 in both sides to eliminate the Denominator 13 on the left leaving variable D only.
(D/13)(13) > -3(13)
D > -39
so... D. D > -39
The value of <em>d</em> is 7.5.
The key to solving equations is doing the inverse, or opposite, function/process.
For example, you subtract when d + 1 = 2:
d + 1 = 2
(d + 1) -1 = (2) - 1
d = 1
In the same way, you add values when you have a negative:
5.5 = -2 + d = d - 2
5.5 = d - 2
(5.5) + 2 = (d - 2) + 2
7.5 = d
Now if instead of adding 2, you subtract 2, the problem becomes:
5.5 = d - 2
(5.5) - 2 = (d - 2) - 2
3.5 = d - 4
This doesn't solve your problem, it just makes the value needed to be canceled out larger.
Thus d = 7.5 and you will add because the value is negative.
To Find :
Position vector at time 
and 
.
Solution :
r (t) = 2 (t −7)i + 12t j
Putting t = 5 s and t = 8 s, we get :
r(5) = 2( -2 )i + 60j
r(5) = -4i + 60j
r(8) = 2i + 96j
Now, to find speed differentiating the r(t) w.r.t t :
Hence, this is the required solution.
Answer:
T(x,y)->(x-3,y-6)
Step-by-step explanation:
Say we take point E and E1. To move E to E1, we need to move it to the left 3 units, already giving us x-3. Then, we need to find out how far down it moved. by counting the units, we can tell that it moved 6 units down as well, giving us y-6. In the end, we get T(x,y)->(x-3,y-6).
