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musickatia [10]
4 years ago
5

A sales team estimates that the number of new phones will sell is a function of the price that it sets. It estimates that if it

sets the price at x dollars, it will sell f(x)=3,776-4x phones. Therefore, the company's revenues is x*(3776-4x).
Mathematics
1 answer:
diamong [38]4 years ago
0 0

Answer:

Revenue = 3,776x-4x^2

Step-by-step explanation:

Revenue is given by = price of product * no. of units of product sold.

Given

price of 1 phone = $x

No. of phone sold = 3,776-4x

Revenue = price of 1 phone*No. of phone sold = x*(3,776-4x)

              = 3,776x-4x^2

Thus, given statement is true.

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Which equation could represent a circle with a center located at (11,-5)
Anon25 [30]
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0
3 years ago
If animals could talk, which would be the rudest.​
sergeinik [125]

Answer:

The dog or a squirrel

Step-by-step explanation:

3 0
3 years ago
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Find the area of figure 1.<br><br> a -12 units2<br> b- 14 units2<br> c- 8 units2<br> d- 10 units2
Brilliant_brown [7]

Answer:

D

Step-by-step explanation:

if you look at the chart. it goes up five and has a width of 2. multiply 5 x 2 = you get 10

3 0
3 years ago
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In arithmetic sequence tn find: S10, if t2=5 and t8=15
makkiz [27]

Given:

\bold{t_2=5}\\\\\bold{t_8=15}\\\\

To find:

\bold{T_n=?}\\\\\bold{S_{10}=?}

Solution:

\to \bold{t_2=5}\\\\  \bold{a+d=5} \\\\  \bold{a=5-d} ................(i)\\\\ \to \bold{t_8=15}\\\\ \bold{a+ 7d=15}.................(ii)\\\\

Putting the equation (i) value into equation (ii):

\to \bold{5-d+7d=15}\\\\\to \bold{5+6d=15}\\\\\to \bold{6d=15-5}\\\\\to \bold{6d=10}\\\\\to \bold{d=\frac{10}{6}}\\\\\to \bold{d=\frac{5}{3}}\\\\

Putting the value of (d) into equation (i):

\to \bold{a=5-\frac{5}{3}}\\\\\to \bold{a=\frac{15-5}{3}}\\\\\to \bold{a=\frac{10}{3}}\\\\

Calculating the \bold{t_n :}

\to \bold{t_n=a+(n-1)d}\\\\\to \bold{t_n=\frac{10}{3}+(n-1)\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}+\frac{5}{3}n-\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}-\frac{5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{10-5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{5}{3} +\frac{5}{3}n}\\\\ \to \bold{t_n=\frac{5}{3}(1+n)}\\\\

Formula:

\bold{S_n = \frac{n}{2}[2a + (n - 1)d ] }\\

Calculating the \bold{S_{10}} :

\to \bold{S_{10} = \frac{10}{2}[2\frac{10}{3} + (10- 1)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + (9)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 9 \times \frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 3\times 5 ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 15 ] }\\\\\to \bold{S_{10} = 5[\frac{20+ 45}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{65}{3} ] }\\\\\to \bold{S_{10} = 5 \times \frac{65}{3}  }\\\\\to \bold{S_{10} =  \frac{325}{3}  }\\\\\to \bold{S_{10} =108.33 }

Therefore, the final answer is  " \bold{\frac{5}{3}(1+n)\ and\ 108.33}"

Learn more:

brainly.com/question/11853909

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photoshop1234 [79]
A general rule of thumb is that if numbers are involved it's quantitative and if characteristics are involved its qualitative, so in this case it'd be quantitative.
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3 years ago
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