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3 years ago

The reading on a car speedometer has 1.6% maximum error the speed limit on the road is 65 miles per hour

Mathematics

1 answer:

nasty-shy [4]3 years ago

3 0

Answer:

For A) it is possible that the speed the cat is going over the speed limit

For B) The statement is false as if the error is negative, the speed of the car will be less than the speed limit.

Step-by-step explanation:

Data provided in the question:

Maximum error on a car speedometer = 1.6% = 0.016

Maximum Speed limit on the road = 65 miles per hour

Now,

The error will be ± 1.6%

Now,

When the speedometer reads 64 miles per hour

The possible speed of the car can be

64 miles per hour + Error

= 64 + [0.016 × 64]

= 64 + 1.024

= 65.024 miles per hour

The speed can be

64 miles per hour - Error

= 64 - [0.016 × 64]

= 64 - 1.024

= 62.976 miles per hour

Hence,

For A) it is possible that the speed the cat is going over the speed limit

For B) The statement is false as if the error is negative, the speed of the car will be less than the speed limit.

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Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10

zvonat [6]

The approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

$FV=P\left(1-\dfrac{r}{100}\right)^n$

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is $n_1$ . Thus, by the above formula for the first car,

$0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}$

Take log both the sides as,

$\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85$

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is $n_2$ . Thus, by the above formula for the second car,

$0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}$

Take log both the sides as,

$\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14$

The difference in the ages of the two cars is,

$d=4.85-3.14\\d=1.71\rm years$

Thus, the approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

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2 years ago

Please help me. This is so confusing.

MrMuchimi

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The vertices of a polygon are given as follows: P(-2,4), Q(4,2), R(4,0); S(-12,0); k = 0.5 Find the coordinates of the vertex P' of the image after a dilation having the given scale factor. Type your answers as a coordinate pair in this format: (x,y)</span>

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3 years ago

Read 2 more answers

A nest of ants has been growing exponentially in such a way that it's population,P, as a function increasing on average more or

ivolga24 [154]

Not sure question is complete, assumptions however

Answer and explanation:

Given the above, the function of the population of the ants can be modelled thus:

P(x)= 1600x

Where x is the number of weeks and assuming exponential growth 1600 is constant for each week

Assuming average number of ants in week 1,2,3 and 4 are given by 1545,1520,1620 and 1630 respectively, then we would round these numbers to the nearest tenth to get 1500, 1500, 1600 and 1600 respectively. In this case the function above wouldn't apply, as growth values vary for each week and would have to be added without using the function.

On one hand, the function above could be used as an estimate given that 1600 is the average growth of the ants per week hence a reasonable estimate of total ants in x weeks can be made using the function.

7 0

3 years ago

Can I PLEASE get some help?

V125BC [204]

The 1st and 3rd choices are irrational. The other 2 are rational. Irrational numbers are numbers that you can't make a simple fraction out of.

7 0

3 years ago

Please help!! I don't know what to do :(

elena55 [62]

Yo sup??

This question can be solved by applying the properties of similar triangles

the triangle with sides 5x and 20 is similar to the triangle with sides 45 and 36

therefore we can say

5x/45=20/36

x=5 units

Hope this helps

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2 years ago