Question

A dish has 212 bacteria in it. The population of the bacteria will grow ata rate of 80% every 2 days. How many bacteria will be present in 9 days?

Answer 1

If they are growing 80% for every twodays, it would be 40% for every one day.

Bacteria after 9 days = 212 * 9 * 40 / 100
= 763.2
To round up, the population of bacteria after 9 days would be 763, with a growth rate of 80% for every two days.