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Verdich [7]
3 years ago
7

Helpppppppppppppppppp

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0
I’m pretty sure that’s true.
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Water is flowing at the rate of 15 km/hr through a pipe of diameter 14 cm into a cuboidal pond
tatyana61 [14]
2 hours.

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tresset_1 [31]

Answer:

C. 30 miles per hour

Step-by-step explanation:

You plug in m = 37.5 into the formula, so:

s = \sqrt{24 * 37.5} \\s = \sqrt{900} \\s = 30

3 0
2 years ago
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3 2/3 subtract 1 11/12​
Gnoma [55]

Hello! Here is your answer to this question! ☺

Answer:

Exact form : 7/4

Decimal form : 1.75

Mixed Number form : 1 3/4

Step-by-step explanation: Covert the mixed number to improper fractions, then find the LCD (Least Common Denominator) and combine.

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3 years ago
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Rebecca has five coins worth $.65 in her pocket. Is she only has quarters and nickels how many quarters does she have?
Trava [24]

Answer:

she can only have 2 quarters

Step-by-step explanation:

a quarter equals 25 cent and 25 plus 25 equals 50 so she has 50 cent in quarters and 15 in nickels so she has 2 quarters and three nickels

8 0
3 years ago
The data below indicate the time (in seconds) that it takes 25 separate employees to complete a certain task. hw1_q5.csva) What
IgorC [24]

Answer:

Explained below.

Step-by-step explanation:

Consider the data provided.

(a)

Compute the mean of the data in seconds as follows:

Mean =AVERAGE(array)

         = 225.280 seconds

(b)

Compute the median of the data in seconds as follows:

Median =QUARTILE.EXC(array,2)

            = 229 seconds

(c)

Compute the variance of the data in seconds as follows:

Variance =VAR.S(array)

              = 1148.043 seconds

(d)

Compute the standard deviation of the data in seconds as follows:

Standard deviation =STDEV.S(F2:F26)

                              = 33.883 seconds.

(e)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

            = 3.755 minutes.

(f)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

            = 3.817 minutes

(g)

Compute the variance of the data in minutes as follows:

Variance =VAR.S(array)

              = 0.319 minutes

(h)

Compute the standard deviation of the data in minutes as follows:

Standard deviation =STDEV.S(F2:F26)

                              = 0.565 minutes.

3 0
3 years ago
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