Answer: try taking it to your media center for help or maybe try connecting to different wifi
Explanation:
Answer:
if(x>12 || x<34)
Explanation:
Mashing the two together using the or '||' operator would allow to run both necessary functions for the next code.
Answer:
C. 220.100.100.45 to 220.100.100.46
Explanation:
The Classless IP subnetting of 220.100.100.0 begins from the fourth octet of the IP address. To get 45 subnet mask, it uses 6 bits from the fourth octet, which approximately give 64 subnets, while the remaining 2 bits are used for host IP addressing.
The useable host IP addresses are gotten from the formula '
-2', with n=2 bits.
useable host IP addresses = 2^2 - 2 = 2 addresses per subnet.
While the 12th subnet is 12 x 2^2 = 44.
This means that the 12th subnet mask starts with 220.100.100.44 (as the network address) and ends with 220.100.100.47 as broadcast IP address, while '.45' and '.46' are the assignable addresses of the subnet.
Answer:
My guess would be C2-C11, But I may be wrong
Imagine a graph
Hope this helps....
Answer:
Following are the solution to the given points:
Explanation:
The Memory address value = 64 bit
The Size of the word 
In point a:
The offset size
( in 1-word block size)
The Index size
(as block number =512)
Tag size
In point b:
The offset size
The Index size 
Tag size 
In point c:
The Ratio at point a

The Ratio at point b
