First, determine the area of the whole circle by the equation, A = πr². Substituting,
A = π(6²) = 36π
Then, multiply this value with the ratio of the given angle to the whole revolution,
A(sector) = 36π x (120° / 360°)
The area of the sector is therefore 12π units².
I believe it's 7.5 but I could be wrong.
Answer:
y = 8
Step-by-step explanation:
y= 
+ 6
= -6
y=(
x 6) + 6
y= 2+6 = 8
Unusual notation. I won't fuss with it.
a. We have isosceles PRT, so angle RPT = angle RTP.
By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.
We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP
Similarly, m angle RPT = 2 m angle MPT
2 m angle MTP = 2 m angle MPT
angle MPT = angle MPT
That's the first part.
b. That makes MPT isosceles.
c. 2x+124=180
2x = 56
x = 28 degrees
MTP = 28 degrees
d. We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees
PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees
Bad drawing, PUT looks acute.
angle PRT = 68 degrees, angle PUT = 96 degrees
