what is the maximum, minimum, quartile 1, median, quartile 3, range, interquartlie range of these numbers " 46,48,50,52, and 54"
Gekata [30.6K]
Min=46
Max=54
1 quartile= 48
Median=50
3 quartile=52
46/48 percent is 95.83%
Elimination:
7x - 3y = 20
5x + 3y = 16
(add)
12x = 36
÷ 12
x = 3
(5 × 3) + 3y = 16
15 + 3y = 16
- 15
3y = 1
÷ 3
y = 1/3
Substitution:
5x + 3y = 16
- 3y
5x = 16 - 3y
÷ 5
x = 3.2 - 0.6y
5(3.2 - 0.6y) + 3y = 16
16 - 3y + 3y = 16
16 = 16
- 16
6y = 0
÷ 6
y = 0
Sorry the substitution messed up for some reason, I'll fix it after I've answered the other question
Answer:
3) 5.4
Step-by-step explanation:
Given two points (x1, f(x1)) and (x2, f(x2)), the average rate of change is computed as follows:
[f(x2) - f(x1)]/[x2 - x1]
From the original photograph to the fourth enlargement, the points are (0, 15) and (4, 36.6). Replacing into the equation we get:
[36.6 - 15]/[4 - 0] = 5.4
Answer:
Given the problem, I believe your answer would be:
h(3)=144
h=48
Hope this helps!