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torisob [31]
3 years ago
11

Rotate the point A (-3,4) 270°about the origin. Plot A' on the grid.

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:

A' (4, 3)

Step-by-step explanation:

you could use the coordinate rule for the rotation of 270 which is (b, -a) this doesnt mean u make the things negative or positive it means that you are switching the y coordinate to where the x coordinate is and making the x coordinate the opposite symbol of what it is, sorry if this make no sense lol

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How many positive integers can be expressed ad a product of two or more of the prime numbers 5,7,11,and 13 if no one product is
sertanlavr [38]

Answer:

11 positive integers can be expressed.

Step-by-step explanation:

Consider the provided information.

The number of possible prime numbers are 5,7,11,and 13.

There are 4 possible prime numbers.

How many positive integers can be expressed as a product of two or more of the prime numbers, that means there can be product of two numbers, three number or four numbers.

The formula to calculate combinations is: ^nC_r=\frac{n!}{r!(n-r)!}

The number of ways are:

^4C_2+^4C_3+^4C_4=\frac{4!}{2!(4-2)!}+\frac{4!}{3!(4-3)!}+\frac{4!}{4!}

^4C_2+^4C_3+^4C_4=\frac{4!}{2!2!}+\frac{4!}{3!}+1

^4C_2+^4C_3+^4C_4=6+4+1

^4C_2+^4C_3+^4C_4=11

Hence, 11 positive integers can be expressed.

8 0
3 years ago
For a particular diamond mine, 81% of the diamonds fail to qualify as "gemstone grade". A random sample of 92 diamonds is analyz
Fed [463]

Answer:

68.79% probability that more than 79% of the sample diamonds fail to qualify as gemstone grade

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 92, p = 0.81

So

\mu = E(X) = np = 92*0.81 = 74.52

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{92*0.81*0.19} = 3.76

Find the probability that more than 79% of the sample diamonds fail to qualify as gemstone grade.

This is 1 subtracted by the pvalue of Z when X = 0.79*92 = 72.68. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{72.68 - 74.52}{3.76}

Z = -0.49

Z = -0.49 has a pvalue of 0.3121

1 - 0.3121 = 0.6879

68.79% probability that more than 79% of the sample diamonds fail to qualify as gemstone grade

4 0
4 years ago
Which compound most likely contains polar covalent bonds?<br> NaCl<br> AlF3<br> Br2<br> NF3
belka [17]

Answer: The correct answer is NF_3

Explanation:

In NF_3 molecule, there are three bond pairs and one lone pair present in the molecule. In a molecule, lone pair present on the nitrogen atom will have a dipole moment in upward direction where as total dipole moment formed by three fluorine atoms will be more in magnitude and it will be directed in downward direction which means that the net dipole moment will be in downward direction. As shown in image attached.

Hence, covalent bond present between nitrogen and fluorine will become polar in nature.

So, the correct answer is NF_3.

7 0
3 years ago
Read 2 more answers
Am I correct? If not what did I do wrong
LUCKY_DIMON [66]

    You are not correct. Here's an explanation as to why: First of all, the triangle is isosceles, since it has two congruent sides that leads to the conclusion of two congruent angles, one opposite each side. This means that all three angle measurements of the triangle are x degrees, x degrees, and 40 degrees. To solve for x, add all three values together and set them equal to 180 degrees, the sum of three angles in any triangle. Your mistake is adding only one x to 40, which isn't inclusive of all three triangles. I hope this helped!

5 0
4 years ago
1. a) if 60%% students passed in Physics, 55% pass in Math and 40% fail in both subjects, what percent of students are pass in b
hammer [34]

Answer:

75%

Step-by-step explanation:

Percent.<em> </em><em>of students passed who in physics</em> =<em>60</em><em>%</em><em> </em><em>Percent</em><em>.</em><em> </em><em>of</em><em> </em><em>students</em><em> </em><em>who</em><em> </em><em>passed</em><em> </em><em>in</em><em> </em><em>maths</em><em> </em><em>=</em><em> </em><em>5</em><em>5</em><em>%</em>

<em>Total</em><em> </em><em>percent</em><em>.</em><em> </em><em>who</em><em> </em><em>passed</em><em> </em><em>=</em><em> </em><em>(</em><em>6</em><em>0</em><em>+</em><em>5</em><em>5</em><em>)</em><em>%</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>1</em><em>5</em><em>%</em>

<em>Percent</em><em>.</em><em> </em><em>of</em><em> </em><em>students</em><em> </em><em>who</em><em> </em><em>failed</em><em>=</em><em> </em><em>4</em><em>0</em><em>%</em>

<em>Percent</em><em>.</em><em> </em><em>of</em><em> </em><em>students</em><em> </em><em>who</em><em> </em><em>passed</em><em> </em><em>=</em><em> </em><em>(</em><em>1</em><em>1</em><em>5</em><em> </em><em>-</em><em> </em><em>4</em><em>0</em><em>)</em><em>%</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>7</em><em>5</em><em>%</em><em>.</em><em> </em>

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2 years ago
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