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Marizza181 [45]
3 years ago
5

What are the lengths of sides KN and NM of the kite? KN = units NM = units

Mathematics
2 answers:
Natalka [10]3 years ago
7 0
Y+10= 2y+5
10=y+5
5=y

Plug this in
(5)+10=15 for KN


2x+6=3x-1
6=x-1
7=x

Plug this value in
2(7)+6
14+6= 20 for NM
Nimfa-mama [501]3 years ago
6 0

<u>Answer-</u>

\boxed{\boxed{KN=15\ units,\ NM=20\ units}}

<u>Solution-</u>

As given in the graph,

KN=KL,\ and\ MN=ML

And,

KN=y+10\\\\KL=2y+5\\\\MN=2x+6\\\\ML=3x-1

Then,

\Rightarrow y+10=2y+5

\Rightarrow 2y-y=10-5

\Rightarrow y=5

And,

\Rightarrow 2x+6=3x-1

\Rightarrow 3x-2x=6+1

\Rightarrow x=7

Therefore,

KN=y+10=5+10=15\ units

NM=2x+6=2\cdot 7+6=14+6=20\ units


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Answer:

56

Step-by-step explanation:

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3 years ago
taylor has an online bank account that charges a fees of 2.3% on each deposit. what is the fee for a deposit of $62.50 each. rou
worty [1.4K]
You need to divide by the number 2.3 and 62.50 and then round to the nearest cent


4 0
3 years ago
Part 2: Use the information provided to write the vertex form equation of each parabola.
Serggg [28]

Answer:   1.  x = -2(y - 4)² + 1

                2.  x = -y² + 5

                3.  y = -5(x + 1)² + 2

<u>Step-by-step explanation:</u>

Notes: The vertex formula of a parabola is x = a(y - k)² + h  or  y = a(x - h)² + k

  • (h, k) is the vertex
  • p is the distance from the vertex to the focus

    \bullet\quad a=\dfrac{1}{4p}

1)

\text{Vertex}=(1,4)\qquad \text{Focus}:\bigg(\dfrac{7}{8},4\bigg)\\\\\text{Given}: (h,k)=(1,4)\\\\\\p=focus-vertex=\dfrac{7}{8}-\dfrac{8}{8}=\dfrac{-1}{8}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{-1}{8})}=\dfrac{1}{-\frac{1}{2}}=-2

Now input a = -2 and (h, k) = (1, 4) into the equation x = a(y - k)² + h

x = -2(y - 4)² + 1

***********************************************************************************

2)

\text{Vertex}=(5,0)\qquad \text{Directrix}:x=\dfrac{21}{4}\\\\\text{Given}: (h,k)=(5,0)\\\\\\p=vertex-directrix=\dfrac{20}{4}-\dfrac{21}{4}=\dfrac{-1}{4}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{-1}{4})}=\dfrac{1}{-1}=-1

Now input a = -1 and (h, k) = (5, 0) into the equation x = a(y - k)² + h

x = -1(y - 0)² + 5    →    x = -y² + 5

***********************************************************************************

3)

\text{Vertex}=(-1,2)\qquad \text{Directrix}:y=\dfrac{41}{20}\\\\\text{Given}: (h,k)=(-1,2)\\\\\\p=vertex-directrix=\dfrac{40}{20}-\dfrac{41}{20}=\dfrac{-1}{20}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{-1}{20})}=\dfrac{1}{-\frac{1}{5}}=-5

Now input a = -5 and (h, k) = (-1, 2) into the equation y = a(x - h)² + k

y = -5(x + 1)² + 2

8 0
3 years ago
What is the equation in slope intercept form of s like that passes through the points (3,2) and (-5,-8)
noname [10]

The slope of the line =  (2- -8) / (3 - - 5) = 10 / 8

= 5/4

y -  y1 = m(x - x1)  where m = slope and (x1, y1) is a point on the line so here we have:-

y - 2 = 5/4(x - 3)

y = 5/4x  - 15/4 + 2

y = 5/4 x - 7/4  is the answer

7 0
3 years ago
Read 2 more answers
When a store had Sold 2/5 of the shirts that were on display, they brought out another 30 from the stockroom. The store likes to
Inga [223]

Answer:

Part A) 3/5 is the total number of shirts remaining on display after selling 2/5

Part B) x \geq 200 (All real whole numbers greater than or equal to 200 shirts)

Part C) Initially on display were the amount of 200 or more shirts

Step-by-step explanation:

Let

x-------> total number of shirts on display

we know that

The inequality that represent the situation is

(1-\frac{2}{5})x+30 \geq 150

(\frac{3}{5})x+30 \geq 150

Part A)  Explain what 3/5 means in the inequality

3/5 is the total number of shirts remaining on display after selling 2/5

Part B) Solve the inequality

we have

(\frac{3}{5})x+30 \geq 150

Subtract 30 both sides

(\frac{3}{5})x \geq 150-30

(\frac{3}{5})x \geq 120

Multiply by 5/3 both sides

x \geq 120(5/3)

x \geq 200\ shirts\ on\ display

Part C) Explain what the solution means in the situation

1) Initially on display were the amount of 200 or more shirts

2) 2/5 were sold and 120 or more shirts were left on display.

3) The store brought out another 30 shirts from the stockroom and placed them on display, for a total of 150 shirts or more on display

8 0
3 years ago
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