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Diano4ka-milaya [45]
2 years ago
14

Help! Scroll to see image!

Mathematics
2 answers:
Olegator [25]2 years ago
4 0

mhorn seems to be correct

Step-by-step explanation:

yshahaa

RoseWind [281]2 years ago
4 0

Answer:

C is correct

Step-by-step explanation:

Please give me brainliest :)

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Which expressions are equivalent to 4(4x + 2y + x − y)? (1 point)
Citrus2011 [14]
=4(4x+2y+x-y)
=4*4x+4*2y+4*x-4*y
=16x+8y+4x-4y
=16x+4x+8y-4y
=20x+4y

donc la bonne reponse est la 3
4(5x+y)*
=4*5x+4*y
=20x+4y
5 0
2 years ago
Can someone pleaseeee hellpp??
monitta

Answer:

5.8

Step-by-step explanation:

To get the mean, add up all the numbers

9+4+8+3+5 = 29

Then divide by how many numbers there are (5)

29/5 =5.8

The mean is 5.8

4 0
3 years ago
I need some help please
MariettaO [177]
Ok so what you will do is 3-18 then you will add 1 and make is to 400X1
4 0
3 years ago
From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
Marquis wrote the linear regression equation y=1.245*-3.684
Advocard [28]
I would say 35 because if you put in 35 for x you get 39.891
5 0
3 years ago
Read 2 more answers
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