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tester [92]
3 years ago
15

WILL GIVE BRAINLIEST, PLEASE HELP ASAP!!! MY LIFE DEPENDS ON THIS!!!

Mathematics
1 answer:
ahrayia [7]3 years ago
7 0

h(x) = 3 * (2)^x

Section A is from x = 1 to x = 2

h(1) = 3 * (2)^1 = 3 * 2 = 6

h(2) = 3 * (2)^2 = 3 * 4 = 12

so

the average rate of change  = (12 - 6)/(2 - 1) = 6


Section B is from x = 3 to x = 4

h(3) = 3 * (2)^3 = 3 * 8 = 24

h(4) = 3 * (2)^4 = 3 * 16 = 48

so

the average rate of change  = (48 - 24)/(4 - 3) = 24


Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

the average rate of change of section B is 24 and the average rate of change of section A is 6

So 24/6 = 4

The average rate of change of Section B is 4 times greater than the average rate of change of Section A

It's exponential function, not a linear function; so the rate of change is increasing.

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I'm in 10th grade so I'll see what I can do and will answer to the best of my ability.

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Using an ideal gas equation to solve the problem. Then the original volume is 17.67 liters.

<h3>What is an ideal gas equation?</h3>

An ideal gas is a theoretical composed of a set of randomly moving gas particles that interact only through elastic collision.

Given

A balloon containing 0.500 mol at 0. 00°C and 65.0 kPa pressure are expanded by adding more argon.

Pressure (P) = 65 kPa

Mole (n) = 0.5 mol

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Universal gas constant (R) = 8.317 L.kPa/mol.K

We know the ideal gas equation

\rm PV =nRT\\\\V \ \ = \dfrac{nRT}{P}

Put the values, we have

\rm V = \dfrac{0.5*8.317*273.15}{65}\\\\V = 17.67

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More about the ideal gas equation link is given below.

brainly.com/question/4147359

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