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3 years ago

WILL GIVE BRAINLIEST, PLEASE HELP ASAP!!! MY LIFE DEPENDS ON THIS!!!

Mathematics

1 answer:

ahrayia [7]3 years ago

7 0

h(x) = 3 * (2)^x

Section A is from x = 1 to x = 2

h(1) = 3 * (2)^1 = 3 * 2 = 6

h(2) = 3 * (2)^2 = 3 * 4 = 12

the average rate of change = (12 - 6)/(2 - 1) = 6

Section B is from x = 3 to x = 4

h(3) = 3 * (2)^3 = 3 * 8 = 24

h(4) = 3 * (2)^4 = 3 * 16 = 48

the average rate of change = (48 - 24)/(4 - 3) = 24

Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

the average rate of change of section B is 24 and the average rate of change of section A is 6

So 24/6 = 4

The average rate of change of Section B is 4 times greater than the average rate of change of Section A

It's exponential function, not a linear function; so the rate of change is increasing.

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Since $cos(\theta) = -\frac{3}{4}$ we can get some information from this. First of all $cos(\theta)$ is defined as $\frac{adjacent}{hypotenuse}$ . So the adjacent side is 3 and the hypotenuse is 4. Using this we can find the opposite side to find $sin(\theta)$ to calculate csc and cot of theta. So using the Pythagorean Theorem we can solve for the missing side. Also I forget to mention we have to calculate the sign of the adjacent side and the hypotenuse. Since you're given that the angle is in quadrant 2, that means the x-value is going to be negative, and the y-value is going to be negative. And the x really represents the adjacent side and the y represents the opposite. So the adjacent side is what's negative. and the opposite is positive

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$a^2+b^2=c^2$

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$b^2 = 7$

$b = \sqrt{7}$

So now we can calculate $sin(\theta)$ .

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Now to calculate cot(theta) you find the inverse of tan. Tan is defined as $tan(\theta) = \frac{sin(\theta)}{cos(\theta)}$ . So all you do is take the inverse which is $cot(\theta) = \frac{cos(\theta)}{sin(\theta)}$ .