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Reika [66]
3 years ago
13

A total of 3 cards are chosen at random, without replacing them, from a standard deck of 52 playing cards. What is the probabili

ty of choosing 3 king cards? 113⋅351⋅125=15525 113⋅113⋅113=313 452⋅352⋅252=417576 113⋅113⋅113=42197
Mathematics
1 answer:
Minchanka [31]3 years ago
4 0

Answer: \dfrac{1}{5525}

Step-by-step explanation:

The total number of cards =52

The number of kings in the cards = 4

If repetition is not allowed , then the total number of ways of choosing 3 cards will be :-

52\times51\times50=132600

The number of ways of choosing 3 kings will be :-

4\times3\times2=24

Now, the probability of choosing 3 king cards will be :-

\dfrac{24}{132600}=\dfrac{1}{5525}

Hence, the  probability of choosing 3 king cards  =\dfrac{1}{5525}

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3 years ago
6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

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Read more about lines of intersections at:

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